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-Dominant- [34]
3 years ago
9

Hermina cut a 10 by 15 piece of cardboard down the diagonal

Mathematics
1 answer:
katen-ka-za [31]3 years ago
8 0

Answer:

\sqrt{325}

Step-by-step explanation:

This is because you use Pythagorean theorem. a^2 + b^2 = c^2.

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Factor the expression 54x+8154x+81 using the GCF.<br> 54x+81=54x+81=
nadya68 [22]
We know that GCF stands for Greatest Common Factor and hence we need to apply this in solving the given problem. The solution is shown below:
54x+8154x+81
Combine same terms, we have:
8208X+81
Factoring with the greatest common factor which is 27
304x+3
The answer for the factored expression is 304X + 3.

6 0
3 years ago
Plz plz plz plz help me​
Mrac [35]

Answer:

Solution given:

perpendicular [P]=15m

base[B]=8m

hypotenuse [H]=17m

rate :4 plants per square metre

no of plants=?

we have

Area of triangular garden: ½(P*B)=½(15*8)=60m²

Now

Total no of plants =rate ×Area =4×60=240

Michael needs <u>240</u> plants in the garden

3 0
3 years ago
Jerome's credit card has an APR of 18%, calculated on the previous monthly balance, and a minimum payment of 2%, starting the mo
galben [10]

Answer:

195.54

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Slove for x. 12x+7&lt;-11 or 5x-8&gt;40​
Elan Coil [88]

Answer:

x<-3/2, x>48/5

Step-by-step explanation:

12x+7<-11

12x<-18

x<-3/2

5x-8>40

5x>48

x>48/5

Hope this helps!

5 0
2 years ago
Determine which equation is parallel to the line JK and which is perpendicular to like JK
sattari [20]

Answer:

If the equation of JK is y = mx + c, then y = mx + c' is the equation of the straight line parallel to above and y = - \frac{1}{m}x + b will be perpendicular to that.

Step-by-step explanation:

Let us assume that the line JK has the equation in slope-intercept form as  

y = mx + c ............. (1)

Therefore, the equation has slope = m

Now, any straight line having an equation with slope m will be parallel to line JK.

So, the equation of the straight line which is parallel to equation (1) will be  

y = mx + c', where, c' is any real constant.

Now, let us assume that another straight line having equation  

y = nx + a is perpendicular to the line JK i.e. equation (1).

Now, we know if two lines are perpendicular to each other then the product of their slopes will be - 1.

So, mn = - 1

⇒ n = - \frac{1}{m}

Therefore, the equation of a straight line which is perpendicular to equation (1) will be y = - \frac{1}{m}x + b where b is any real constant. (Answer)

3 0
3 years ago
Read 2 more answers
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