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3 years ago

The elevation of Location 1 is 20 feet above sea level and the elevation of Location 2 is 50 feet below sea level.

Mathematics

2 answers:

bearhunter [10]3 years ago

8 0

Answer:

Step-by-step explanation:

Location 1 is 20 feet ABOVE the sea level while Location 2 is 50 feet BELOW the sea level.

Location 1 would be 20

Location 2 would be -50

And think of the greater than and lesser than symbol as a alligators mouth it would go towards the bigger number so, -50 < 20, Location 1 is higher, is the answer.

noname [10]3 years ago

4 0

Your answer is C i think!

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Mateo ordered a package of

Lapatulllka [165]

Answer:Each tennis ball cost 0.67 cents.

Step-by-step explanation:

$10.05 divided by 15 equals 0.67 cents.

0.67 x 15 = $10.05

7 0

3 years ago

Michael breeds chickens and ducks. Last month, he sold 505050 chickens and 303030 ducks for \$550$550dollar sign, 550. This mont

GenaCL600 [577]

Let the cost of a chicken be x and the cost of a duck, y, then

50x + 30y = 550 . . . (1)
44x + 36y = 532 . . . (2)

(1) x 6 ⇒ 300x + 180y = 3,300 . . . (3)
(2) x 5 ⇒ 220x + 180y = 2,660 . . . (4)

(3) - (4) ⇒ 80x = 640
⇒ x = 640 / 80 = 8

From (1): 50(8) + 30y = 550
⇒ 30y = 550 - 400 = 150
⇒ y = 150 / 30 = 5

Therefore, the price of a chicken is $8 and the price of a duck is $5.

4 0

4 years ago

Reflected over the x-axis, then translated 6<br> units left

lapo4ka [179]

Take the original coordinate (x,y)
to reflect over x-axis change it to (x,-y)
*basically change the sign of y*
to translate 6 units left (x-6,y)
* basically subtract 6 from x
So your new point should be (x-6,-y)

7 0

3 years ago

Your weekly salary is $150. you also earn $20 commission for each cell phone that you sell. write an expression to represent the

Vlad1618 [11]

150 + 20x, where x is the number of cellphones sold

6 0

4 years ago

Given that (ax^2 + bx + 3) (x + d) = x^3 + 6x^2 + 11x + 12<br> a + 2b - d = ?

Mariulka [41]

Answer:

Let's solve for a.

(ax2+bx+3)(x+d)=x3+6x2+11x+12a+2b−d

Step 1: Add -12a to both sides.

adx2+ax3+bdx+bx2+3d+3x+−12a=x3+6x2+12a+2b−d+11x+−12a

adx2+ax3+bdx+bx2−12a+3d+3x=x3+6x2+2b−d+11x

Step 2: Add -bdx to both sides.

adx2+ax3+bdx+bx2−12a+3d+3x+−bdx=x3+6x2+2b−d+11x+−bdx

adx2+ax3+bx2−12a+3d+3x=−bdx+x3+6x2+2b−d+11x

Step 3: Add -bx^2 to both sides.

adx2+ax3+bx2−12a+3d+3x+−bx2=−bdx+x3+6x2+2b−d+11x+−bx2

adx2+ax3−12a+3d+3x=−bdx−bx2+x3+6x2+2b−d+11x

Step 4: Add -3d to both sides.

adx2+ax3−12a+3d+3x+−3d=−bdx−bx2+x3+6x2+2b−d+11x+−3d

adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

adx2+ax3−12a+3x+−3x=−bdx−bx2+x3+6x2+2b−4d+11x+−3x

adx2+ax3−12a=−bdx−bx2+x3+6x2+2b−4d+8x

Step 6: Factor out variable a.

a(dx2+x3−12)=−bdx−bx2+x3+6x2+2b−4d+8x

Step 7: Divide both sides by dx^2+x^3-12.

a(dx2+x3−12)

dx2+x3−12

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

Answer:

−bdx−bx2+x3+6x2+2b−4d+8x/

dx2+x3−12

Step-by-step explanation:

8 0

3 years ago