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2 years ago

Consider the equation 3x + 1 = 2x + 5

Mathematics

1 answer:

fomenos2 years ago

3 0

You can’t technically solve it because there’s no question

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A paving company is preparing to build a driveway that will be 40 feet long and 12 feet wide. They will start with an 18 inch la

svetlana [45]

Answer:27

Step-by-step explanation:first you need 40 x 12 for the area for your gravel

so 480 divided by 18 = about 27

3 0

3 years ago

TRUE OR FALSE? The equation of a line with slope m = -3 and including point (5, 5) is y = -3x + 20.

kodGreya [7K]

Answer:

True.

Step-by-step explanation:

y = -3x + 20

Put x as 5, then y output should be 5.

y = -3(5) + 20

y = -15 + 20

y = 5

True, the line with slope -3 passes through points (5, 5).

8 0

2 years ago

Read 2 more answers

It takes you 0.8 of a minute to read each page of your health book.It takes you 5.5 minutes to take the test at the end.How long

Nina [5.8K]

So you divide 0.8 by 6.25 and your answer is 7.8125 and then you add 5.5 minutes of your other number and you get the answer of 13.3125

6 0

2 years ago

How to solve by completing the square

AveGali [126]

https://www.mesacc.edu/~scotz47781/mat120/notes/quad_formula/quad_formula.html

Use this link to help you .

6 0

2 years ago

For the following demand equation compute the elasticity of demand and determine whether the demand is elastic, unitary, or inel

adelina 88 [10]

Answer:

Demand is inelastic at p = 9 and therefore revenue will increase with

an increase in price.

Step-by-step explanation:

Given a demand function that gives <em>q</em> in terms of <em>p</em>, the elasticity of demand is

$E=|\frac{p}{q}\cdot \frac{dq}{dp} |$

If E < 1, we say demand is inelastic. In this case, raising prices increases revenue.
If E > 1, we say demand is elastic. In this case, raising prices decreases revenue.
If E = 1, we say demand is unitary.

We have the following demand equation $D(p)=-\frac{3}{4}p+29$ ; p = 9

Applying the above definition of elasticity of demand we get:

$E(p)=\frac{p}{q}\cdot \frac{dq}{dp}$

where

p = 9
q = $-\frac{3}{4}p+29$
$\frac{dq}{dp}=\frac{d}{dp}(-\frac{3}{4}p+29)$

$\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{d}{dp}\left(\frac{3}{4}p\right)+\frac{d}{dp}\left(29\right)\\\\\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{3}{4}$

Substituting the values

$E(9)=\frac{9}{-\frac{3}{4}(9)+29}\cdot -\frac{3}{4}\\\\E(9)=\frac{36}{89}\cdot -\frac{3}{4}\\\\E(9)=-\frac{27}{89}\approx -0.30337$

$|E(9)|=|\frac{27}{89}| < 1$

Demand is inelastic at p = 9 and therefore revenue will increase with an increase in price.

6 0

2 years ago