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ki77a [65]
3 years ago
12

Will give ✨brainliest✨ to first who answers and explains or shows work. helpppop me plz

Mathematics
1 answer:
eimsori [14]3 years ago
4 0
X^2/9 +7/3


~I believe this is the answer.
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Round .00085 to the nearest thousandth. 0.0008 0.0009 0.0010 0.001
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The answer is 0.0009 because when you have a 5 behind the number you are trying to round, you round up
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3 years ago
What are the coordinates of the vertices of the pre-image given? ry= −x ◦ T1, −2(x, y) 
nataly862011 [7]
<h3><u>Answer:</u></h3>

Hence, the coordinates of pre-image are:

A(1,6) , B(0,4) , C(3,4) , D(2,6)

<h3><u>Step-by-step explanation:</u></h3>

We have to find the  coordinates of the vertices of the pre-image given?

Ry= −x ◦ T_1, −2(x, y)

i.e. we have to find the composition of reflection along the line y=-x and translation with the rule:

(x,y) → (x+1,y-2)

Now we have coordinates of A",B",C" and D" as:

A"(-4,-2)

B"(-2,-1)

C"(-2,-4)

D"(-4,-3)

Now we are asked to find the coordinates of the pre-image.

Also when any point is reflected along y=-x then the point is transformed to:

(x,y) → (-y,-x)

Let A,B,C and D are the points of the pre-image.

Hence, the coordinates of the pre-image are given as:

so, the transformation is given as:

A→A'→A"

B→B'→B"

C→C'→C"

D→D'→D"

Where A',B',C',D' represents the transformation after translation and A",B",C",D" represents the transformation after reflection as well.

The coordinates of A' are (2,4)

B' are (1,2)

C' are (4,2)

and D' are (3,4)

Now, the coordinates of pre-image are given as:

A'(x,y)  → A(x-1,y+2)=A(1,6)

B'(x,y)  → B(x-1,y+2)=B(0,4)

C'(x,y)  → C(x-1,y+2)=C(3,4)

and D'(x,y)  → D(x-1,y+2)=D(2,6)

Hence, the coordinates of pre-image are:

A(1,6) , B(0,4) , C(3,4) , D(2,6)

4 0
3 years ago
11 times 11 in binary . Help i need it today!
Sunny_sXe [5.5K]

Answer:

1011×1011 = 11110011

Step-by-step explanation:

11 in binary is 1011

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8 0
2 years ago
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Help please my brain hurts
34kurt

Answer:

Do it yourself

Step-by-step explanation:

8 0
3 years ago
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