Answer:
The vertex form parabola y = 2( x+4)² -37
Step-by-step explanation:
<u>Step(i):-</u>
Given parabola equation j(x) = 2x² + 8x -5
Let y = 2x² + 8x -5
⇒ y = 2(x² + 2(4x)+(4)²-(4)²) -5
By using (a + b)² = a² +2ab +b²
y = 2(x+4)²- 32 -5
y = 2 ( x-(-4))² -37
<u><em>Step(ii):-</em></u>
The vertex form parabola y = a( x-h)² +k
The vertex form parabola y = 2(x+4)² -37
Answer:
66
Step-by-step explanation:
42+8x
= 42+8(3)
= 42+24
= 66
x equals 4 and y equals 5 . so the formula would be 5x+12y=80 and if we need 4 of the small boxes we sub x for 4 and we get 5(4) =20. Next, 80 minus 20 is 60, and the equation would now be 12y=60. we now divide both sides by 12 and we get left with y=5. 5x + 12y = 80 5(4) + 12(5)=80 20+60=80. That is all. I hope that doesn't sound confusing
Answer:
y cannot be -9
Step-by-step explanation:
The other word is discontinuity
It is what y cannot be
The denominator cannot be zero so
y+9 cannot be zero
y cannot be -9
