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Molodets [167]
3 years ago
8

What is the answer the this question??????

Mathematics
1 answer:
Tema [17]3 years ago
3 0
The answer should be -4
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For what values of a are the following expressions true?<br><br><br> |a+5|=−5−a<br><br> plz help
ANEK [815]
The answer is just a=0, you have to cross out the fives
6 0
3 years ago
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Alex buys a top of the line computer. He did not realize that the computer would lose value so fast. If his computer cost $1800.
Natali [406]

This can be solve by using the formula

D = P( 1 – i)^n

Where d is the depreciation value after n years

P is the initial value

i is the depreciation rate

n is the years

D = 1/3 ( 1800)

D = 600

So

600 = 1800 ( 1- 0.45)^n

Solve for n

<span>N = 1.83 years</span>

3 0
3 years ago
Find the value of the expression 2x2 - 4x2 + 7x – 7 if x= 3. What is the value if x = 2?
vichka [17]

Answer:

if x= 3, so it's 32  if x= 2, so it's 7

Step-by-step explanation:

5 0
3 years ago
According to the line plot, what is the total weight gained by the dogs that gained 1/8 f a pound or 3/4 of a pound?
erik [133]

3 1/8

First you take the all the dogs that gained 3/4 (which is 4)
Then you multiply it by 4

3/4x4=3
Then you add the dogs that gained 1/8 of a pound

3+1/8=3 1/8

4 0
2 years ago
A cone with radius 5 units is shown below. Its volume is 105 cubic units. Find the height of the cone.
Ainat [17]

Answer:

height of the cone  = 4.01273885 units

Step-by-step explanation:

Volume of a cone(V) is given by:

V = \frac{1}{3} \pi r^2h             ....[1]

where,

r is the radius and h is the height of the cone.

As per the statement:

A cone with radius 5 units and ts volume is 105 cubic units

⇒r = 5 units and V = 105 cubic units

Substitute these given values and use \pi = 3.14 in [1] we have;

105 = \frac{1}{3} \cdot 3.14 \cdot 5^2 \cdot h

Multiply both sides by 3 we have;

⇒315 = 78.5 \cdot h

Divide both sides by 78.5 we have;

4.01273885 = h

or

h = 4.01273885 units

Therefore, the height of the cone is, 4.01273885 units

6 0
3 years ago
Read 2 more answers
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