I thought it was the one above it but I think you are right tho
Answer:
,nm
Step-by-step explanation:
Step-by-step explanation:
1) The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length....
= Solution ,
Length ( L ) = ?
breadth ( b ) = 10xy cm
area ( a ) = ( 30x² + 20xy )
Now ,
area ( a ) = l × b
or, ( 30x²y + 20xy ) = L × 10xy cm
![or,\frac{30 {xy + 20xy}^{2} }{10xy} = l \\](https://tex.z-dn.net/?f=or%2C%5Cfrac%7B30%20%7Bxy%20%2B%2020xy%7D%5E%7B2%7D%20%7D%7B10xy%7D%20%20%3D%20l%20%5C%5C%20)
![or, \: l = 3 {x}^{2 - 1} + 2cm](https://tex.z-dn.net/?f=or%2C%20%5C%3A%20l%20%3D%203%20%7Bx%7D%5E%7B2%20-%201%7D%20%20%2B%202cm)
![\boxed{\sf{l = (3x+2)cm}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%7Bl%20%3D%20%283x%2B2%29cm%7D%7D)
2) Subtract the quotient when 20x⁴y² is divided by 5x³y from the product of 2x and 3y.
= Solution,
![= \frac{20 {x}^{4} {y}^{2} }{5 {x}^{3} y} \\](https://tex.z-dn.net/?f=%20%20%3D%20%5Cfrac%7B20%20%7Bx%7D%5E%7B4%7D%20%7By%7D%5E%7B2%7D%20%20%7D%7B5%20%7Bx%7D%5E%7B3%7D%20y%7D%20%20%20%5C%5C%20)
![= 4xy](https://tex.z-dn.net/?f=%20%3D%204xy)
The product of 3x and 4y = 6xy
= 6x - 4xy
![= \boxed{\sf {2xy}}](https://tex.z-dn.net/?f=%20%3D%20%5Cboxed%7B%5Csf%20%7B2xy%7D%7D)
hope it helped !!!!
Answer:
20
Step-by-step explanation:
Divisors of 100
1, 2, 4, 5, 10, 20, 25, 50, 100
Given :
A right angle triangle ABC .
To Find :
The perimeter of ABC .
Solution :
Since, triangle ABC is right angled and angle ∠ABC is 46° .
So, AC = AB cos 46° = 7.64 units.
Also, CB = AB sin 46° = 7.91 units.
Therefore, the perimeter of ΔABC is :
P = 11 + 7.64 + 7.91 units
P = 26.55 units
Hence, this is the required solution.