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slavikrds [6]
3 years ago
13

The teachers of the two classes want to compare the heights of their students. Which statements about the data sets are accurate

? Select three options. Because the sets are symmetrical, the mean should be used to compare the data sets. Because the sets do not contain outliers, the MAD should be used to compare the data sets. Because the sets are not symmetrical, the IQR should be used to compare the data sets. Because the sets contain outliers, the median should be used to compare the data sets. The mean and mode cannot be accurately determined based on the type of data display.
Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
8 0

This question is incomplete.

Complete question

The sets of data below show the heights, in inches, of students in two different preschool classes.

A) a box plot titled class 1.

The number line goes from 38 to 49. the whiskers range from 39 to 48, and the box ranges from 40 to 43. a line divides the box at 41.

class 1

B) A box plot titled class 2.

The number line goes from 38 to 49. the whiskers range from 38 to 49, and the box ranges from 39 to 42. a line divides the box at 41.

class 2

The teachers of the two classes want to compare the heights of their students. Which statements about the data sets are accurate? Select three options.

• Because the sets are symmetrical, the mean should be used to compare the data sets.

• Because the sets do not contain outliers, the MAD should be used to compare the data sets.

•Because the sets are not symmetrical, the IQR should be used to compare the data sets.

•Because the sets contain outliers, the median should be used to compare the data sets.

•The mean and mode cannot be accurately determined based on the type of data display.

Answer:

• Because the sets are not symmetrical, the IQR should be used to compare the data sets.

• Because the sets contain outliers, the median should be used to compare the data sets.

• The mean and mode cannot be accurately determined based on the type of data display.

Step-by-step explanation:

In the above question, we can see that a teacher intends to compare the heights of students from two different classes.

Because the data sets to be obtained would contain heights from different classes the results obtained would be non symmetrical.

Hence the best statistical analysis to use to solve for or to compare a set of non symmetrical data is known as either the Median or an Interquartile range.

It is important to note that a non symmetrical data would most likely contain or include the presence of outliers.

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allochka39001 [22]
I am not entirely certain of what you mean in all of these problems but I will try to solve them to the best of my ability.
It appears you have asked three seperate questions.
A) What is f(1) when the f(x) = 5x+1
To solve this, you can simply substitute in 1 any time you see an x.
This means
f(x) = 5x+1
becomes
f(1) = 5(1) + 1
From there you need only solve the problem using the order of operations. There is nothing to solve inside parentheses, nor are there exponents, so you can just skip straight to multiplication
f(1) = 5 + .1
And then addition.
f(1)=6
Therefore, if the f(x) = 5x +1, the f(1) = 6
B)  If  the f(x) =\frac{2x + 3}{5} what is the f ^{-1}(3)
 I do not have much experience solving problems like this, but I will try to help you. 
So the f-1(3) is the inverse function of three. That means that it's basically the same only reversed.The way to find the inverse of f(x) =\frac{2x + 3}{5} would be to substitute f(x) for a y, and then switch the x's and y's, so that it becomes 
x = \frac{2y+3}{5}
then simplify and solve that. 
5x = 2y+3
5x-3 = 2y
\frac{(5x-3)}{2} =y
<span>y= \frac{(5x-3)}{2}
</span>Then once more substitute the y for f(x), and you have the inverse function of x
f(x) = \frac{(5x-3)}{2}
From there you can just solve for the f(3)
First substitute in the 3,
f(3) =\frac{(5(3)-3)}{2}
Then, follow the order of operations
Parentheses
f(3) = \frac{(15-3)}{2}
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In this case, the f-1(3) = 6 if <span>f(x) =\frac{2x + 3}{5}
However, I am not 100 percent certain that is the correct way to go about solving this problem, so I am also going to try solving it a different way here, in hopes that someone else will know what is correct.

Since ordinarily, when solving for the inverse of a function written as f-1(x), you would switch x and y, when solving the inverse of a function written as f-1(3), perhaps it would be correct to switch 3 and y. I will now attempt to solve this in this way.
</span>If  the f(x) =\frac{2x + 3}{5} what is the f ^{-1}(3)
So the way I would go about this is to first substitute in the 3, replacing all x's
f-1(3)= <span>\frac{(2(3) + 3)}{5}
Then I would replace f-1(3) with y
y = </span><span>\frac{(2(3) + 3)}{5} 
</span>And switch the y with the tree i just substituted in as an x
3= <span>\frac{(2(y) + 3)}{5} 
</span>Then I would only need to solve the problem, first isolating the variable, and then simplifying as far as possible.
In the process of isolating the y, I would first multiply by five to remove the fraction,
15= 2y+3
Then subtract 3
12=2y
and divide by 2 to remove the coefficient
6=y
and reverse the two sides for the sake of convenience.
y=6
Then I would change y back to f-1(3) to keep things consistent.
f-1(3) = 6.

Either way, you get the same answer, I am just uncertain as to which is the technically correct method.

C)<span>3y − 7 = y + 5
</span>This is a fairly simple problem, and the solution can be found by moving the variables and numbers so that each is on its own side of the equal sign, then multiplying or dividing until it is further simplified.
First, rewrite the problem
<span>3y − 7 = y + 5
</span>Then, move the numbers so that they are all on one side. In this case, I will do so by adding 7
3y =y +5 +7
3y =y+12
Then move the variables so they are all on the same side. In this case, I am subtracting y from both sides.
3y -y = 12
2y = 12
And finally, I will divide by 2 to further simplify
y = 12
<span>3y − 7 = y + 5 simplified, is y = 12</span>


4 0
4 years ago
A sandbox is twice as long as it is wide. It’s area is 72in square. What is the perimeter of the sandbox?
melamori03 [73]

Answer:

let the width be 'x'

length = 2x

Area = 72 in square

(2x)(x)= 72

2x^2=72

x^2=36

x=6

perimeter = 2(l+b)

=2(2x+x)

=2(3x)

=2(3*6)

=2(18)

=36 inches

therefore the answer is option D

Hope it helps.............

6 0
3 years ago
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mart [117]

Answer:

x=-9

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Step-by-step explanation:

3x+10y=13 ← Equation 1

4(-2y+x)-9x=13\\

By simplifying the above equation we get,

-8y+=4x-9x=13 (Simplifying the brackets)

-8y-5x=13 (By subtracting -9x from +4x) ← Equation 2

Multiply Equation 1 by 5 and Equation 2 by 3 and add them together.

Equation 1 multiplied by 5 will give,

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Equation 2 multiplied by 3 will give,

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26y=104 (After simplifying x values)

Therefor y=4

By substituting y=4 to Equation 1 we get,

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x=-9

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Answer:

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