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Harrizon [31]
3 years ago
9

1. 3. 2. 4. Which shapes will fold into a box with no lid?

Mathematics
2 answers:
vladimir2022 [97]3 years ago
5 0

Answer: The answer is 1 and 3

:)

luda_lava [24]3 years ago
5 0
I agree, your answer is 1 & 3.
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A?

Step-by-step explanation:

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Which of the following statements is TRUE?
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<span>Which of the following statements is TRUE?

</span>b. An equation that is an IDENTITY has one solution.
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4 years ago
What is the solution to this equation x +13=34​
Rzqust [24]

Answer:

21

Step-by-step explanation:

To find this answer you would have to subtract the total number from one of the numbers adding to equal the total which in this case it would be 34-13.

34-13

=21

So the answer would be 21.

plz give brainliest :'D

6 0
3 years ago
Read 2 more answers
Help plz down below with the question
Lapatulllka [165]

Answer:

The SAS Postulate

Step-by-step explanation:

SAS means Side-Angle-Side; that is, two sides are equal and an angle <em>between </em>those sides are equal. We're given two sides: TK and TL, and we're given that 1 is congruent to 2. Knowing the latter, we can conclude that the angle between them (let's call it 1.5 for our purposes) will be congruent to itself. Since 1.5 is the angle right in the middle of two congruent sides, our answer is SAS.

4 0
4 years ago
Solve step by step solution then only i can do it plxx ​
Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So \triangle ABC and \triangle ABD Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
  • First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

  • We need to find base=b

According to Pythagoras thereon

{\boxed{\sf b^2=h^2-p^2}}

  • Substitutethe values

\longrightarrow\sf b^2=10^2-p^2

\longrightarrow\sf b={\sqrt {10^2-8^2}}

\longrightarrow\sf b={\sqrt{100-64}}

\longrightarrow\bf b={\sqrt {36}}

\longrightarrow\sf b=6

\therefore\overline{BC}=6cm

  • BD=BC+CD

\longrightarrowBD=9+6

\longrightarrowBD=15cm

  • Now in \triangle ABD

Perpendicular=p=8cm

Base =b=15cm

  • We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

{\boxed {\sf h^2=p^2+b^2}}

  • Substitute the values

\longrightarrow\sf h^2=8^2+15^2

\longrightarrow\sf h={\sqrt {8^2+15^2}}

\longrightarrow\sf h={\sqrt {64+225}}

\longrightarrow\sf h={\sqrt {289}}

\longrightarrow\sf h=17cm

\therefore{\underline{\boxed{\bf x=17cm}}}

3 0
3 years ago
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