Answer
Sol: The correct answer is b. three planes that contain point B are ABD, AEF and DHF.
I think it may be 5+3 and carry the one up top to get the sum of 56.
i dont quite get the question but...
i guess this is how it is.
Take the mirror image of∆ABC Through the a line through the point y=3.
The new ∆ABC would have point C=(4,2)
B=(3,-6) A=(1,-3)
Now shifting the ∆ABC one unit (<em>i.e. 2 acc. to the graph as scale is 1 unit =2</em>) towards right ( or <em>adding 2 to the x coordinates of ∆ABC)</em>
We get the Coordinates of triangle ABC as A=(3,-3) B=(5,-6) C=(6,2).
This coordinate is the same coordinates of ∆A"B"C".
Hope it helps...
Regards;
Leukonov/Olegion.
Answer:
∅ = 90°
Step-by-step explanation:
Given;
sin2∅=2sin∅
sin2∅ = 2sin∅Cos∅
but, Sin²∅ + Cos²∅ = 1
Cos²∅ = 1 - Sin²∅
Cos ∅ = √(1 - Sin²∅)
sin2∅=2sin∅ ↓
2sin∅Cos∅ = 2sin∅
2sin∅(√(1 - Sin²∅)) = 2sin∅
Let Sin∅ = P
2P( √(1 - P²)) = 2P
Divide both sides by 2P
√(1 - P²) = 1
Square both sides
1 - P² = 1
P² = 1 - 1
P² = 0
P = 0
Recall, Sin∅ = P
Sin∅ = 0
∅ = Sin ⁻¹(0)
∅ = 90°
