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lukranit [14]
3 years ago
10

Jordan buys chocolate bars from Costco for $0.75 each. He marks them up by 165% to sell at a volleyball game. How much does he c

harge for the chocolate bars? *
A $0.49
B $1.24
C $1.99
D $2.40
Mathematics
1 answer:
Flura [38]3 years ago
4 0
The anwser is b bc it’s 1.237 you round
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A large rectangular card measures 80 centimetres by 90 centimetres.
Dimas [21]

1200 cards

All measurements should be taken in centimeters

<u>Calculate the area of large rectangular card</u>:

  • Length * Width
  • 80 * 90
  • 7200 cm²

<u>Calculate the area of each small cards</u>:

  • Length * Width
  • 4 * 1.5
  • 6 cm²

<u>Divide the area of large card by area of small card</u>

  • 7200 cm² ÷ 6 cm²
  • 1200

Number of small cards: 1200 cards

5 0
2 years ago
Read 2 more answers
Identify the type I error and the type II error for a hypothesis test of the indicated claim. The percentage of adults who retir
matrenka [14]

Answer:

<u>Type I error: </u>D. Reject the null hypothesis that the percentage of adults who retire at age 65 is less than or equal to 62 % when it is actually true.

<u>Type II error: </u>A. Fail to reject the null hypothesis that the percentage of adults who retire at age 65 is less than or equal to 62 % when it is actually false.

Step-by-step explanation:

A type I error happens when a true null hypothesis is rejected.

A type II error happens when a false null hypothesis is failed to be rejected.

In this case, where the alternative hypothesis is that "the percentage of adults who retire at age 65 is greater than 62%", the null hypothesis will state that this percentage is not significantly greater than 62%.

A type I error would happen when the conclusion is that the percentage is greater than 62%, when in fact it is not.

A type II error would happen when there is no enough evidence to claim that the percentage is greater than 62%, even when the percentage is in fact greater than 62% (but we still don't have evidence to prove it).

5 0
4 years ago
for a normal distribution curve with the mean of 15 and a standard deviation of 5, which range of the variable defines an area u
kipiarov [429]
Using empirical rule,
Upper range of 68%=15+5=20
Lower range =10
Range=10
8 0
3 years ago
What is the midpoint of CD given the coordinates C(-4,8) and D(8,-4)?
adelina 88 [10]
<span>The answer is B. (2, 2).
The midpoint (M) of two points (x1, y1) and (x2, y2) is:
M = ((x1 + x2)/2, (y1 + y2)/2).
We know that the points of CD are C(-4, 8) and D(8, -4). So we have:
x1 = -4, y1 = 8, x2 = 8, y2 = -4.
Now when we have all we need, let's calculate the midpoint M.
M = ((x1 + x2)/2, (y1 + y2)/2);
M = (((-4) + 8)/2, (8 + (-4))/2);
M = ((8 - 4)/2, (8 - 4)/2);
M = (4/2, 4/2); M = (2, 2).
Therefore, the midpoint of CD is (2, 2).</span>
4 0
3 years ago
I=$24, P=$400, t=2 years The annual interest rate is %.
kolbaska11 [484]

<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>ans</em><em> </em><em>is</em><em> </em><em>3</em><em>%</em><em>.</em>

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8 0
4 years ago
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