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Romashka [77]
4 years ago
10

The area of an oil spill is doubling in size every day. At the start of the day on May 1, the oil spill covers 20 square meters.

During which day will the area exceed 500 square meters?
Mathematics
1 answer:
ozzi4 years ago
5 0

Answer:

May 6

Step-by-step explanation:

20 x 2 = 40 40 x 2 = 80 80 x 2 = 160 x 2 = 320 320 x 2 = 640 after 5 days on may 6 it will surpass 500 meters.

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Someone please help me I’m actually struggling so much rn.
alexandr1967 [171]

Answer:

Step-by-step explanation:

okay don't feel bad, you actually got it right, let me help you with some holes!

You calculate slope by the rise over run. These people are confusing you a bit - do problem 2 then 1

the vertical change is -1 horizontal change is 3 so by rise/run=-1/3

-1/3 is the slope

for the second problem this is confusing but just read and try to analyze

vertical change/horizontal change = 5-4/0-3= 1/-3(or -1/3)

The y intercept is the point where the line hits the y axis, so at point (0, 5)

The function is y=mx+b

m is the slope

b is the y intercept

so y=-1/3x+5

7 0
3 years ago
Question 8(Multiple Choice Worth 3 points)
Nastasia [14]
Answer: C) F(4) = 0

Detailed Explanation:

A zero/root of a polynomial is a value of the variable which makes the value of the polynomial to 0.

Therefore, when (x - 4) is a Factor :-
=> x - 4 = 0
=> x = 4

=> x = 4 is the Zero of the Polynomial.
4 0
2 years ago
HELP IS THIS correct??? !!!
Allushta [10]

Answer:

No

Step-by-step explanation:

                                            x           y

y = - 3(-2) + 1 =  7                -2        7        

y = -3(0) +1 = 1                      0         1

y = -3(1) + 1 = -2                    1          -2

y = -3(3) + 1 = -8                   3      -8

8 0
3 years ago
Suppose that a box contains one fair coin (Heads and Tails are equally likely) and one coin with Heads on each side. Suppose fur
stealth61 [152]

Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Three heads.
  • Event B: Fair coin.

The probability associated with 3 heads are:

  • 0.5^3 = 0.125 out of 0.5(fair coin).
  • 1 out of 0.5(biased).

Hence:

P(A) = 0.125 + 0.5 = 0.625

The probability of 3 heads and the fair coin is:

P(A \cap B) = 0.5(0.125) = 0.0625

Then, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0625}{0.625} = 0.1

0.1 = 10% probability that the chosen coin was the fair coin.

A similar problem is given at brainly.com/question/14398287

4 0
3 years ago
Are the expressions 3+y and 13(6+y) equivalent?
ira [324]

Answer: no because 13(6+y) is 78+ 13y

Step-by-step explanation:

4 0
3 years ago
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