Number defective=4
number of non-defective=total-defective
=20-4
=16
the questions asked for 1 defective
so we choose only 1 defective from 4 defective items
4C1
and for 1 non-defective
we choose only 1 non-defective from 16 non-defective items
16C1
we choose 2 items from 20 items
so 20C2
answer:
probability= [(4C1) * (16C1)] /(20C2)
=32/95
Our P = 100, r = .08, n = 1 (annually means once a year), and t = 15. Filling in accordingly, we have

. Simplifying a bit gives us

and

. Raising that number inside the parenthesis to the 15th power gives us

. Multiplying to finish means that A(t) = $317.22
You do 9x27=243 then take 2x31=62 add 243+62=305 then take 305 and subtract it from 28 305-28=277
so if i did it right you should get n=277
6-3x=2x
In order to solve these, you first want to get all the variables on one side. So, you add 3x to both sides.
6=x
The answer is x=6
Hope this helps!
Step-by-step explanation:
it's 2x²+8x
and I cannot understand your question