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dem82 [27]
3 years ago
12

Somebody, please help! This is my exam.

Mathematics
2 answers:
Arlecino [84]3 years ago
8 0

Answer:

The answer is A or B but I think A more

Step-by-step explanation:

Kazeer [188]3 years ago
7 0
Answer is B if it isn’t I’m sorry
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A rectangular pyramid. The rectangular base has a length of 10 inches and a width of 6 inches. 2 triangular sides have a base of
melisa1 [442]

Answer:

Answer:

a) The base of the rectangular pyramid shown has an area of

60 square inches

b) A triangular face with a base of 10 inches has an area of 28 square inches.

c) A triangular face with a base of 5 inches has an area of 17.75 square inches.

d) The total surface area of the pyramid is 151.5 square inches.

Step-by-step explanation:

a) Solving for question a, we were given the following parameters

A rectangular pyramid. The rectangular base has a length of 10 inches and a width of 6 inches

The formula used to calculate the rectangular base of a rectangular pyramid =

Length × Width

Where :

Length = 10 inches

Width = 6 inches

Rectangular base = 10 inches × 6 inches

= 60 inches²

Hence, the base of the rectangular pyramid shown has an area of 60 square inches

b) Solving for question b, we have the following values given:

2 triangular sides have a base of 10 inches and height of 5.6 inches.

First step would be to solve for one triangular side first.

The area of the one triangular side = (Base × Height) ÷ 2

= (10 inches × 5.6 inches) ÷ 2

= 56inches² ÷ 2

= 28 inches²

Therefore, for the 2 triangular sides, since they have the same base and height, the other side as well would be 28 inches².

A triangular face with a base of 10 inches has an area of 28 square inches.

c) Solving for question c, the following parameters are given:

2 triangular sides have a base of 5 inches and height of 7.1 inches.

We would be to solving for one triangular side first.

The area of the one triangular side = (Base × Height) ÷ 2

= (5 inches × 7.1 inches) ÷ 2

= 35.5 inches² ÷ 2

= 17.75 inches²

Therefore, for the 2 triangular sides, since they have the same base and height, the other side as well would be 17.75 inches².

A triangular face with a base of 5 inches has an area of 17.75 square inches.

d) Solving for d, it is important to note that, a rectangular pyramid has 5 faces and they are: The rectangular base and 4 triangular faces

The formula for the total surface area of the rectangular pyramid is given as

Total Surface Area of the rectangular pyramid = Rectangular Base + Area of Triangular Side A + Area of Triangular Side B + Area of Triangular Side C + Area of Triangular Side D + Area of Triangular Side E

Total Surface Area of the Rectangular Pyramid = 60 inches² + 28 inches² + 28 inches² + 17.75 inches² + 17.75 inches²

Total surface Area of the Rectangular pyramid = 151.5 inches²

The total surface area of the pyramid is 151.5 square inches.

Step-by-step explanation:

BRAINLIEST PLEASE?

3 0
3 years ago
The line contains the point (-4,-4) and is perpendicular to a line with a slope of 5/2 . The equation is this line is ?
Trava [24]

Answer:

2x + 5y + 28 = 0

Step-by-step explanation:

since they are perpendicular,

m1 ×m2 = -1

5/2 × m2 = -1

m2 = -2/5

now,

y -y1 = M (x-x1)

y - (-4) = -2/5 ( x - (-4) )

y +4 = -2/5 ( x + 4 )

5 ( y +4 ) = -2 ( x+4)

5y +20 = -2x - 8

2x + 5y +20 + 8 =0

2x + 5y + 28 = 0

3 0
3 years ago
What is the degree measure of f?
olganol [36]
The answer is 58 pretty sure
7 0
3 years ago
It's in the attachment <br> URGENT
maxonik [38]

Step-by-step explanation:

\frac{2a}{a + b - c}  =  \frac{2b}{b + c - a}  =  \frac{2c}{a + c - b}  = k \\  \\ by \: theorem \: on \: equal \: ratios \\   \\ \frac{2a + 2b + 2c}{a + b - c + b + c - a + a + c - b}  = k \\  \\  \frac{2(a + b + c)}{a + b + c}  = k \\ \\   \therefore \: k = 2

5 0
3 years ago
Which of the following choices is closest to the distance (in miles) between points A and B? (5 points)
pshichka [43]

Answer:

i think it's B 3.46

Step-by-step explanation:

hope this helps

5 0
3 years ago
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