Answer: Let, n(U) be=x only (p)=x/5 only(ca)=16 n(pnc)=?n(c)=60%ofx=0.6x
then,
Only (c)=n(c)-n(cnp)
16=0.6x-n(cnp)
n(cnp)=0.6x-16
again,
n(U)=only(p)+only (c)+n(cnp)+n(pUc)of complement
x=x/5+16+0.6x-16+8
5x=x+3x+40
x=40
n(cnp)=0.6x-16=0.6×40-16=8
Step-by-step explanation:
Answer: \frac{x+3}{x+4}
Step-by-step explanation:
\frac{x^2-9}{x^2+x-12}
\frac{(x+3)(x-3)}{(x+4)(x-3)} =\frac{x+3}{x+4}
Answer:
d = 35(4) + 55(t)
Step-by-step explanation:
35 * 4 then added to 55 * the hours that "t" equals will then equal the total distance traveled, d
Use substitution to solve for x and y.
X=2, y=6
