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enyata [817]
3 years ago
9

What is the volume of the pyramid?

Mathematics
1 answer:
stealth61 [152]3 years ago
5 0

Answer: 484

Step-by-step explanation:

12x11x11=1,452

1,452/3=484

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What is the slope of the line that is parallel to y=3x-4
kipiarov [429]

Answer:

3 also could be said as 3/1

Step-by-step explanation:


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3 years ago
Find the area of the trapezoid.
vekshin1

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18

Step-by-step explanation:

7 - 5 = 2

triangle = bh/2

triangle = 2(3) / 2

triangle = 3

rect = bh

rect = 3 x 5

rect = 15

trapezoid = 15 + 3

trapezoid = 18

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2 years ago
Guided Practice
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Answer: y( 1 - 7y2 + 15y7)

Step-by-step explanation:Just put () around the 1 threw 15 and put the y out  of the ()

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3 years ago
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Rowan has $50 in a savings jar and is putting in $5 every week. He wants to buy shoes worth no more than $250. can someone give
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250= 50 + 5x
That should be it
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4 years ago
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The force of gravity on Mars is different than on Earth. The function of the same situation on Mars would be represented by the
sweet-ann [11.9K]

Answer:

If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.

Step-by-step explanation:

Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

v=v_0+a\,*\,t\\y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.

Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

v=v_0+a\,*\,t\\0=v_0-g\,*\,t\\t=\frac{v_0}{t}

When we use this to replace the 't" in the displacement formula, we et:

y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2\\y-y_0=v_0\,(\frac{v_0}{g} )-\frac{g}{2} \,(\frac{v_0}{g} )^2\\y-y_0=\frac{1}{2} \frac{v_0^2}{g}

This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)

And we can also answer the question about time, since given the same initial velocity v_0 , the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)

3 0
3 years ago
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