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Sati [7]
3 years ago
8

Solve the system of equations using substitution. 4x + y = 32 y = 4x

Mathematics
2 answers:
Lynna [10]3 years ago
5 0

Answer:

(4,16)

Step-by-step explanation:

y=16 x=4

stellarik [79]3 years ago
4 0

Answer:

4x + y = 32

y = 4x

4x+4x=32

8x=32

x=4

y=16

Step-by-step explanation:

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3 years ago
Initially, there are 40 grams of A and 50 grams of B, and for each gram of B, 2 grams of A is used. It is observed that 15 grams
hram777 [196]

Answer:

X(16)=25.71grams

Step-by-step explanation:

let X(t) denote grams of C formed in  t mins.

For X grams of C we have:

\frac{2}{3}Xg of A and \frac{1}{3}Xg of B

Amounts of A,B remaining at any given time is expressed as:

40-\frac{2}{3}Xg of A and  50-\frac{1}{3}Xg  of B

Rate at which C is formed satisfies:

\frac{dX}{dt} \infty(40-\frac{2}{3}X)(50-\frac{1}{3}X)->\frac{dX}{dt}=k(90-X)\\\therefore \frac{dX}{(90-X)^2}=kdt->\int{\frac{dX}{(90-X)^2}} \, =\int {k} \, dt  \\\therefore \frac{1}{90-X}=kt+c->90-X=\frac{1}{kt+c}\\\\X(t)=90-\frac{1}{kt+c}

Apply the initial condition,X(0)=0 ,to the expression above

0=90-\frac{1}{c} \ \ ->c=\frac{1}{90}\\\therefore\\X(t)=90-\frac{1}{kt+\frac{1}{90}} \ \ ->X(t)=90-\frac{90}{90kt+c}

Now at X(8)=15:

15=90-\frac{90}{90\times 8k+1}  \ ->75=\frac{90}{720k+1}\\k=0.0002778

Substitute  in X(t) to get

X(t)=90-\frac{90}{0.0002778t\times 90+1}\\X(t)=90-\frac{90}{0.25t+1}\\But \ t=16\\\therefore X(t)=90-\frac{90}{0.025\times16+1}\\X(t)=25.71

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3 years ago
Which fraction is between
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The answer is D) -5/16


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80% of 60 is 1/5 of what number?
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Well, if 80% of 60 is 48, and 48x5 is 240, 80% of 60 is 240.

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Hope this helps! Xo


7 0
3 years ago
Use the figure below to complete the sentence.
kvasek [131]
Answer- vertical;congruent
4 0
2 years ago
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