Answer:
hahaha
Step-by-step explanation:
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The answer is 6n^3+n^2+6n-4 I hope I helped you!
Usando un sistema de ecuaciones, se encuentra que
- Cada manzana cuesta $3.
- Cada pera cuesta $1.
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- Un sistema de ecuaciones soluciona esta pergunta.
- El custo de una manzana es x.
- El custo de una pera es y.
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- <u>Seis manzanas y 8 peras cuestan $26</u>, o sea,

- <u>Cada manzana cuesta el triple de cada pera</u>, o sea,

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Primero, encontramos el cuesto de una pera, substituyendo la segunda en la primera ecuación.






Cada pera cuesta $1.
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<u>Cada manzana cuesta el triple de cada pera</u>, o sea,
.
Cada manzana cuesta $3.
Se encuentra um problema similar en brainly.com/question/24646137
since keyra types 80 words in two minutes it means than he types 40 words in a minute then she types 40x3=120 words in three minutes
Step-by-step explanation:
Since, line contains the point (-8, 11) and has a y intercept of 5.
Therefore, line passes through the points (-8, 11) and (0, 5)
Equation of line in two point form is given as:

Hence, 6x + 11y - 55 = 0 is the required equation of line.