3/4 of 12 is 9
12 - 9 =3
3 sections are left
1.25 also bc they are parallel
Answer:
90 cm²
Step-by-step explanation:
The area of the shaded portion is the area of parallelogram ABCD minus the area of triangle EBC.
ABCD is a parallelogram with base 18 cm and height 10 cm.
A(parallelogram) = bh = (18 cm)(10 cm) = 180 cm²
EBC is a triangle with base 18 cm and height 10 cm.
A(triangle) = bh/2 = (18 cm)(10 cm)/2 = 180 cm²/2 = 90 cm²
shaded area = 180 cm² - 90 cm² = 90 cm²
Answer:
The third side is sqrt(77)
Step-by-step explanation:
Since this is a right triangle we can use the Pythagorean theorem
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
2^2 + b^2 = 9^2
4+ b^2 = 81
Subtract 4 from each side
b^2 = 81-4
b^2=77
Take the square root of each side
sqrt(b^2) = sqrt(77)
b = sqrt(77)
The third side is sqrt(77)
The area of the smallest side of the right triangle is 25 ft².
<h3>What is a right-angle triangle?</h3>
A triangle having two sides at an angle of 90 degrees is called the right-angle triangle.
Note:- The figure is missing in the question I am attaching the complete figure with the answer below for calculation.
Given that:-
The hypotenuse = 169 ft ² = 13 ft
The side with area 144 ft² = 12 ft
Using Pythagoras' identity to find the third side x ( smallest )
x² + 12² = 13²
x² + 144 = 169 ( subtract 144 from both sides )
x² = 25 ( take the square root of both sides )
x = 5
Thus the area of the smallest side will be calculated as:-
A = 5²
A = 25 ft²
Therefore the area of the smallest side of the right triangle is 25 ft².
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