Answer:
step 1
Find the average growth per year of the populations of rabbits farm A
Over the first 2 years
for t=0
numbers of rabbits=5 (is not exact)
for t=2
numbers of rabbits=40
average=[40-5]/2---------> 17.5
step 2
Find the average growth per year of the populations of rabbits farm B
Over the first 2 years
for t=0
numbers of rabbits=5 (is not exact)
for t=2
numbers of rabbits=30
average=[30-5]/2---------> 12.5
step 3
Compare the average growth per year of the populations of rabbits on both farms
farm A=17.5
farm B=12.5
the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 5 rabbits per year.
therefore
the answer is the option C)
the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 6 rabbits per year.
Step-by-step explanation:
Y ( 2 ) = - 5.131 · 2² + 31.821 · 2 - 3.3333 =
= - 5.131 · 4 + 63.642 - 3.3333 = -20.524 + 63.642 - 3.3333 = 39.78 ≈ 40
Answer: B ) 40.
Answer:
-18k^2+72kx+54x^2
Step-by-step explanation:
Sorry i don't have the step-by-step but that's the answer
Answer:
Step-by-step explanation:
You can divide 50 by 5 (2+(1.50x2)) 50/5 is 10 10x + 20y.
Happy studying ^-^
