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gogolik [260]
3 years ago
10

Which of the following histograms represents this set of data?

Mathematics
1 answer:
Zinaida [17]3 years ago
3 0
The second from the top
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A bakery is collecting data to investigate how changing the price charged for a loaf of bread affects the bakery’s daily profit.
RSB [31]

Considering the vertex of the graph, it is found that the quadratic function that is the best model for the data is given by:

y = -200(x - 4)^2 + 800

<h3>What is the equation of a quadratic function given it’s vertex?</h3>

The equation of a quadratic function, of vertex (h,k), is given by:

y = a(x - h)^2 + k

In which a is the leading coefficient.

Researching the problem on the internet, it is found that the vertex is at point (4,800), hence h = 4 and k = 800.

y = a(x - 4)^2 + 800

It has a value of y = 0 at x = 6, hence:

0 = a(6 - 4)^2 + 800

a = -200

Thus, the model is:

y = -200(x - 4)^2 + 800

More can be learned about quadratic functions at brainly.com/question/24737967

6 0
2 years ago
The scale of a room in a blueprint is 3in:5ft. A wall in the same blueprint is 18in. Plzzz complete table
postnew [5]

we know that

[scale]=[blueprint]/[actual]-------> [actual]=[blueprint]/[scale]

[scale]=3/5 in/ft

for [wall blueprint]=18 in

[wall actual]=[wall blueprint]/[scale]-------> 18/(3/5)----> 30 ft

Part A)

the actual wall is 30 ft  long

Part B) window has actual width of 2.5 ft

[ window blueprint]=[scale]*[actual window]-----> (3/5)*2.5----> 1.5 in

the width of the window in the blueprint is 1.5 in

Part C) Complete the table

For [blueprint length]=4 in

[actual length]=[blueprint length]/[scale]-------> 4/(3/5)----> 20/3 ft

For [blueprint length]=5 in

[actual length]=[blueprint length]/[scale]-------> 5/(3/5)----> 25/3 ft

For [blueprint length]=6 in

[actual length]=[blueprint length]/[scale]-------> 6/(3/5)----> 30/3=10 ft

For [blueprint length]=7 in

[actual length]=[blueprint length]/[scale]-------> 7/(3/5)----> 35/3 ft

For [actual length]=6 ft

[blueprint length]=[actual length]*[scale]-------> 6*(3/5)----> 18/5 in

For [actual length]=7 ft

[blueprint length]=[actual length]*[scale]-------> 7*(3/5)----> 21/5 in

For [actual length]=8 ft

[blueprint length]=[actual length]*[scale]-------> 8*(3/5)----> 24/5 in

For [actual length]=9 ft

[blueprint length]=[actual length]*[scale]-------> 9*(3/5)----> 27/5 in

6 0
3 years ago
Dimitri is helping to plan the school talent show. Each performer for the talent show has 6 66 minutes for his or her performanc
antoniya [11.8K]
The talent show consists of introduction and talent performance. It could be written into this equation
Talent show duration= introduction + talent performance

Each performer for the talent show has 6 minutes for their show, the <span>introduction of the talent show is 24 minutes, and the total duration should be 150 minutes. Then, maximum performance count of the show would be:
</span>
Talent show duration= introduction + talent performance
<span>150 min = 24 min + (performance count * 6min)
</span>performance count = (150min - 24min) / 6 min
performance count=21
7 0
3 years ago
Please help, i gotta get my grade up
insens350 [35]
You can plug them each of them into a graphing calculator into y= and then check the table and compare which one is correct. Hope this helps
8 0
3 years ago
In the xy-plane, the graph of function f(x) has zeros at −5, −2, and 2. Write the polynomial function.
Alona [7]

Answer:

f(x) = x^3 +5x^2-4x-20

Step-by-step explanation:

Given

Zeros: -5,-2,2

Required

The polynomial function

If a function has a, b and c as its zeros, the function is:

f(x) = (x - a)(x - b)(x - c)

So, we have:

Zeros: -5,-2,2

f(x) = (x - (-5))(x - (-2))(x - 2)

Open the inner brackets

f(x) = (x +5)(x +2)(x - 2)

Expand the difference of two squares

f(x) = (x +5)(x^2 - 4)

Expand

f(x) = x^3 +5x^2-4x-20

4 0
3 years ago
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