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blondinia [14]
3 years ago
12

Mitosis occurs during which phase?

Chemistry
1 answer:
lara [203]3 years ago
8 0

Answer:

Prophase

Explanation:

Prophase is the first stage in mitosis, occurring after the conclusion of the G2 portion of interphase. During prophase, the parent cell chromosomes — which were duplicated during S phase — condense and become thousands of times more compact than they were during interphase.

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When 38^88Sr decays to 34^84Kr, a(n) ______________ is emitted
navik [9.2K]

Answer:

The correct answer is - alpha particle and positron.

Explanation:

In this question, it is given that, 38^88Sr decays to 34^84Kr, which means there is an atomic number decrease by 4, 38 to 34, and atomic mass decreases by 4 as well 88 to 84.

A decrease in the atomic mass is possible only when there is an emission of the alpha particle as an alpha particle is made of 2 protons and 2 neutrons. If an atom emits an alpha particle, there is a change in atomic number as it decreases by two, and its mass number decreases by four.

So after the emission of an alpha particle, the new atom would be

38^88Sr=> 36^84X => 34^84Kr

so there is also two positron emission that leads to decrease in atomic number by one with each emission:

38^88Sr=> 2^4He+ 36^84X => 36^84X + 2(1^0β+) => 34^84Kr

Positron decay is the conversion of a proton into a neutron with the emission of a positron that causes the atomic number is decreased by one, which causes a change in the elemental identity of the daughter isotope.

3 0
3 years ago
If the a of a monoprotic weak acid is 1. 2×10^−6. What is the [H] of a 0. 31 m solution of this acid?
Vanyuwa [196]

The pH of the solution of the given acid is 3.099

Let  HX  be the weak acid:

HX ⇌  H^{+}+ X^{-}

For which:

K_{a} = [ H^{+}][ X^{-}] / [HX]

If  K_{a} lies in the range 10^{-4} - 10^{-10}we can assume that the equilibrium concentrations used in the expression are a good enough approximation to the initial concentrations.

Rearranging and taking negative logs of both sides gives:

pH = \frac{1}{2} [pK_{a} - loga]

a is the concentration of the acid.

pK_{a} =-logK_{a} = -log (2×10^{-6}) = 5.69

pH = \frac{1}{2} [5.69- (-0.508)]

pH = 3.099

Learn more about pH of acid here;

brainly.com/question/13043236

#SPJ4

3 0
2 years ago
In what way is sedimentary rock formed in nature with a sieve
ella [17]
Sedimentary rock is made of Brocken down rocks and living things.
4 0
3 years ago
What is the molar of mass of copper (II) sulfate CuSOu?
Aleksandr-060686 [28]
191.546,,,,,,,,,,,,,,,,,,,
8 0
3 years ago
Some gas molecules move at speeds of 542 meters per second. How fast is this in miles per hour? 542 =? 1h Solve by dimensional a
artcher [175]

Answer:

1212.42\ \text{mph}

Explanation:

We need to convert 542\ \text{m/s} to \text{miles/hour}

1\ \text{mile}=5280\ \text{ft}

1\ \text{ft}=12\ \text{inches}

5280\ \text{ft}=5280\times 12=63360\ \text{inches}

1\ \text{inch}=2.54\ \text{cm}=0.0254\ \text{m}

63360\ \text{inches}=63360\times 0.0254=1609.344\ \text{m}

So

1\ \text{mile}=1609.344\ \text{m}\\\Rightarrow 1\ \text{m}=\dfrac{1}{1609.34}\ \text{miles}

1\ \text{hour}=60\times 60\ \text{seconds}\\\Rightarrow 1\ \text{s}=\dfrac{1}{3600}\ \text{hour}

542\ \text{m/s}=\dfrac{\dfrac{542}{1609.34}}{\dfrac{1}{3600}}=1212.42\ \text{mph}

The speed of the gas molecules is 1212.42\ \text{mph}.

4 0
3 years ago
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