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3 years ago

Select the term that best completes the following statement:

Chemistry

1 answer:

ankoles [38]3 years ago

3 0

Answer:

C. oxygen atom

Explanation:

H2O contains two hydrogen atoms and one oxygen atom.

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Which best represents a homogeneous mixture of an element and a compound.

Allushta [10]

Answer:

The composition of air this is because it vmade up of oxygen, nitrogen, Nobel gages and Carbon dioxide

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2 years ago

Why is it important to make observations about the reactants?

Free_Kalibri [48]

Answer:

Reason Down below

Explanation:

It is important because when you make observation you get a clue sometimes and it reactants i feel like it also takes places with observation. :)

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3 years ago

Which of the following is an inexhaustible energy resource?

koban [17]

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2 years ago

The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol. In the presence of a catalyst at 37°C, the r

rodikova [14]

Answer:

E₁ ≅ 28.96 kJ/mol

Explanation:

Given that:

The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol,

Let the activation energy for a catalyzed biochemical reaction = E₁

E₁ = ??? (unknown)

Let the activation energy for an uncatalyzed biochemical reaction = E₂

E₂ = 50.0 kJ/mol

= 50,000 J/mol

Temperature (T) = 37°C

= (37+273.15)K

= 310.15K

Rate constant (R) = 8.314 J/mol/k

Also, let the constant rate for the catalyzed biochemical reaction = K₁

let the constant rate for the uncatalyzed biochemical reaction = K₂

If the rate constant for the reaction increases by a factor of 3.50 × 10³ as compared with the uncatalyzed reaction, That implies that:

K₁ = 3.50 × 10³

K₂ = 1

Now, to calculate the activation energy for the catalyzed reaction going by the following above parameter;

we can use the formula for Arrhenius equation;

$K=Ae^{\frac{-E}{RT}}$

If $K_1=Ae^{\frac{-E_1}{RT}} -------equation 1$ &

$K_2=Ae^{\frac{-E_2}{RT}} -------equation 2$

$\frac{K_1}{K_2} = e^{\frac{-E_1-E_2}{RT}$

$E_1= E_2-RT*In(\frac{K_1}{K_2})$

$E_1= 50,000-8.314*310.15*In(\frac{3.50*10^3}{1})$

$E_1 = 28957.39292$ $J/mol$

E₁ ≅ 28.96 kJ/mol

∴ the activation energy for a catalyzed biochemical reaction (E₁) = 28.96 kJ/mol

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2 years ago

Write chemical equations for the following electrolytes dissolving in water

Elden [556K]

$1)NaCl=>Na^{+}+Cl^{-}\\2)PbSO_{4}=>Pb^{2+}+SO_(4)^{2-}$

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2 years ago