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3 years ago

11

Why do we have 2 high tides and 2 low tides a day?

1 answer:

Sunny_sXe [5.5K]3 years ago

5 0

Whereas semidiurnal tides are observed at the equator at all times, most locations north or south of the equator experiencetwo unequal high tides and twounequal low tides per tidal day; this is called a mixed tide and the difference in height between successive high (or low) tides iscalled the diurnal inequality.

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Bezzdna [24]

Answer: It's A

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3 years ago

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7) What is the hydrogen concentration of a solution with a pH of 2.1? *

lesya [120]

Answer:

Hydrogen concentration = 7.94×10^-3 M

Explanation:

from potenz Hydrogen ( pH ) definition

pH = -log[H+]

2.1 = -log[H+]

2.1/-log = -log[H+]/-log

10^-2.1 = [H+]

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3 years ago

A 3.301 mass % aqueous solution of potassium hydroxide has a density of 1.05 g/mL. Calculate the molality of the solution. Give

8_murik_8 [283]

<u>Answer:</u> The molality of potassium hydroxide solution is 0.608 m

<u>Explanation:</u>

We are given:

3.301 mass % of potassium hydroxide solution.

This means that 3.301 grams of potassium hydroxide is present in 100 grams of solution

Mass of solvent = Mass of solution - Mass of solute (KOH)

Mass of solvent = (100 - 3.301) g = 96.699 g

To calculate the molality of solution, we use the equation:

$\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams})}$

Where,

$m_{solute}$ = Given mass of solute (KOH) = 3.301 g

$M_{solute}$ = Molar mass of solute (KOH) = 56.1 g/mol

$W_{solvent}$ = Mass of solvent = 96.699 g

Putting values in above equation, we get:

$\text{Molality of KOH}=\frac{3.301\times 1000}{56.1\times 96.699}\\\\\text{Molality of KOH}=0.608m$

Hence, the molality of potassium hydroxide solution is 0.608 m

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3 years ago

A bus traveled south west for 422 kilometers. The entire trip took 3 hours. Calculate the velocity.

ahrayia [7]

V= d/t
v=speed
d=distance
t=time

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v =140.667m/s

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3 years ago

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The paper in the straw makes the soda fizz.

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3 years ago