Answer:
5.97 mol
Explanation:
To find the number of moles when given the mass of a substance, we divide the mass of the sample by its molar mass.
so, we get,
nN203 = 454 g / 76.01 g /mol
= 5.97 mol
The reaction between the reactants would be:
CH₃NH₂ + HCl ↔ CH₃NH₃⁺ + Cl⁻
Let the conjugate acid undergo hydrolysis. Then, apply the ICE approach.
CH₃NH₃⁺ + H₂O → H₃O⁺ + CH₃NH₂
I 0.11 0 0
C -x +x +x
E 0.11 - x x x
Ka = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
Since the given information is Kb, let's find Ka in terms of Kb.
Ka = Kw/Kb, where Kw = 10⁻¹⁴
So,
Ka = 10⁻¹⁴/5×10⁻⁴ = 2×10⁻¹¹ = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
2×10⁻¹¹ = [x][x]/[0.11-x]
Solving for x,
x = 1.483×10⁻⁶ = [H₃O⁺]
Since pH = -log[H₃O⁺],
pH = -log(1.483×10⁻⁶)
<em>pH = 5.83</em>
The mass of HCHO2 and NaCHO2 to be added to the buffer solution are 0.23g and 0.44g respectively
Data;
- Volume of solution = 260mL
- conc. of HCHO2 = 2.5*10^-2M
- conc. of NaCHO2 = 2.5*10^-2M
<h3>Mass of Reagent Added</h3>
To calculate the mass of reagent added, let's start with HCHO2
The mass of HCHO2 to be added is the number of moles of HCHO2 multiplied by it's molar mass.
The mass of NaCHO2 to be added in the buffer solution is
The mass of HCHO2 and NaCHO2 to be added to the buffer solution are 0.23g and 0.44g respectively
Learn more about buffer solution here;
brainly.com/question/22390063
The strength of electrical forces tells about the size of charge on the object.
<h3>What is infer about the strength of electrical forces?</h3>
The strength of the electric force between two charged objects depends on the amount of charge that each object have and on the distance between the two charges. When the amount of charge gets bigger, the force also gets bigger, and when the distance between the two charges gets larger, the force also gets smaller. Electric forces are the attraction present between two charge bodies.
So we can conclude that The strength of electrical forces tells about the size of charge on the object.
Learn more about force here: brainly.com/question/12970081
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The lighter components are able to rise higher in the column before they are cooled to their condensing temperature, allowing them to be removed at slightly higher levels.
I hope this helps
