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Svetllana [295]
2 years ago
9

If you have 10,000 grams of a substance that decays with a half-life of 14 days, then how much will you have after 56 days?

Chemistry
1 answer:
Crank2 years ago
5 0

Answer: 625 grams

Explanation:

14 goes into 56, 4 times.

10,000÷2=5,000 - first half life

5,000÷2=2,500 - second half life

2,500÷2=1,250 - 3rd half life

1,250÷2= 625 - 4th half life

Note: don't type "grams" after 625, just type "625".

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What is true of a solution of 1.0M HCL
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What is true of a solution of 1.0 M HCl(aq)? It contains 1.0 gram of HCl per 100 grams of water.

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If you had a beaker full of black powder which of the following could you have?
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MnS+HCl H 2 S+MnCl 2 Which set of coefficients would balance the equation?
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3 years ago
A gas has a pressure of 8.5atm and occupies 24L at 25∘C. What volume (in liters) will the gas occupy if the pressure is increase
Vesna [10]

The volume (in liters) that the gas will occupy if the pressure is increased to 13.5 atm and the temperature is decreased to 15 °C is 15 L

From the question given above, the following data were obtained:

Initial pressure (P₁) = 8.5 atm

Initial volume (V₁) = 24 L

Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K

Final pressure (P₂) = 13.5 atm

Final temperature (T₂) = 15 °C = 15 + 273 = 288 K

<h3>Final volume (V₂) =? </h3>

  • The final volume of the gas can be obtained by using the combined gas equation as illustrated below:

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\\\frac{8.5 * 24}{298}  = \frac{13.5 * V_{2}}{288}\\\\ \frac{204}{298} = \frac{13.5 * V_{2}}{288}\\\\

Cross multiply

298 × 13.5 × V₂ = 204 × 288

4023 × V₂ = 58752

Divide both side by 4023

V_{2} = \frac{58752}{4023}\\\\

<h3>V₂ = 15 L </h3>

Therefore, the final volume of the gas is 15 L

Learn more: brainly.com/question/25547148

3 0
2 years ago
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