Answer: One of them is the set {1,2,3,4,5,6}itself; one is the empty set, containing no elements. “Proper subset of a set ” usually denotes a subset in which at least one element of the original set is missing; so one of the subsets - the original set iitself - is not a proper subset. Therefore the answer is 63.
Step-by-step explanation:
Answer:
<h2>c. 2</h2>
Step-by-step explanation:
![4^\frac{1}{3}\cdot4^\frac{1}{6}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=4^{\frac{1}{3}+\frac{1}{6}}=4^{\frac{1\cdot2}{3\cdot2}+\frac{1}{6}}=4^{\frac{2}{6}+\frac{1}{6}}=4^\frac{2+1}{6}=4^\frac{3}{6}=4^\frac{3:3}{6:3}=4^{\frac{1}{2}}\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\=\sqrt[2]{4^1}=\sqrt4=2](https://tex.z-dn.net/?f=4%5E%5Cfrac%7B1%7D%7B3%7D%5Ccdot4%5E%5Cfrac%7B1%7D%7B6%7D%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20a%5En%5Ccdot%20a%5Em%3Da%5E%7Bn%2Bm%7D%5C%5C%5C%5C%3D4%5E%7B%5Cfrac%7B1%7D%7B3%7D%2B%5Cfrac%7B1%7D%7B6%7D%7D%3D4%5E%7B%5Cfrac%7B1%5Ccdot2%7D%7B3%5Ccdot2%7D%2B%5Cfrac%7B1%7D%7B6%7D%7D%3D4%5E%7B%5Cfrac%7B2%7D%7B6%7D%2B%5Cfrac%7B1%7D%7B6%7D%7D%3D4%5E%5Cfrac%7B2%2B1%7D%7B6%7D%3D4%5E%5Cfrac%7B3%7D%7B6%7D%3D4%5E%5Cfrac%7B3%3A3%7D%7B6%3A3%7D%3D4%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20a%5E%5Cfrac%7Bm%7D%7Bn%7D%3D%5Csqrt%5Bn%5D%7Ba%5Em%7D%5C%5C%5C%5C%3D%5Csqrt%5B2%5D%7B4%5E1%7D%3D%5Csqrt4%3D2)
Answer:
x = 5
Step-by-step explanation:
These triangles are similar, so they are in proportion to each other. Because of this we can say 
(the lengths of the vertical sides) = 
(the lengths of the hypotenuses). If we solve by cross-multiplying the numbers and then dividing we get x = 5.
Answer:
I would try going with 12.2
Step-by-step explanation:
If I'm correct this is very simple.
x=15
So plug that into the equation and you get
11.00+0.08x15
which equals 12.2
So I recommend trying that out :)
Answer:
3/5 ÷ 2/3 - fraction calculator. The result is 9/10 = 0.9 = nine tenths.
Step-by-step explanation:
Subnets. Subnets and Hosts. Borrow 2 bits. S S H H H H H H. # of subnets = 22 = 4. Subnet mask = 2 bits = 128 + 64 = 192.
