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3 years ago

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I need help with this alg2

1 answer:

mixas84 [53]3 years ago

4 0

I believe D but i am not sure but your chrome book is about to die !!

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Five friends bought admission tickets the museum and a box lunch.the cost of each admission ticket was $11.75.each box lunch cos

slega [8]

Cost of the admission tickets: 11.75x

Cost of the box lunch: 5x

Expressions to find the total cost = (1) ....... 11.75x + 5x

That is equivalent to: (2) .......... (11.75 + 5)x = 16.75x.

Now calculate the cost for x = 5 using both expressions:

1) 11.75(5) + 5(5) = 58.75 + 25 = 83.75

2) 16.75(5) = 83.75

Of course you got the same result with both expressions.

4 0

3 years ago

Through (2, -1), perp. to y = -2x-3

kramer

9514 1404 393

Answer:

y = 1/2x -2

Step-by-step explanation:

The given equation is in slope-intercept form, so you recognize its slope is -2. The perpendicular line will have a slope that is the opposite reciprocal of that, so is -1/-2 = 1/2.

The y-intercept can be found from ...

b = y -mx . . . . . for line of slope m through point (x, y)

b = -1 -(1/2)(2) = -1 -1 = -2

Then the slope-intercept equation of the perpendicular line is ...

y = 1/2x -2

6 0

2 years ago

If L ll M, classify the marked angle pair and give their relationship, then solve for x

Talja [164]

Answer:

Supplementary angle; x = 14.

Step-by-step explanation:

Angle (9x - 2) and angle (10y + 6) form a straight line, so they form a supplementary angle.

Because angle (9x - 2) and (5x + 54) are corresponding angles, we can set them equal to each other.

9x - 2 = 5x + 54

9x - 5x = 54 + 2

4x = 56

x = 14.

Hope this helps!

5 0

2 years ago

Use a graph to solve<br> 1/2|x + 1| + 1 = |x|

kiruha [24]

1st x is -1, 2nd x is 3

3 0

3 years ago

Verify that the roots of 5x²- 6x -2 = 0 are <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%20%2B%20%5Csqrt%7B19%7D%20%7D%7B5%7D%2

Mice21 [21]

Answer:

Proof below.

Step-by-step explanation:

<u>Quadratic Formula</u>

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

<u>Given quadratic equation</u>:

$5x^2-6x-2=0$

<u>Define the variables</u>:

a = 5
b = -6
c = -2

<u>Substitute</u> the defined variables into the quadratic formula and <u>solve for x</u>:

$\implies x=\dfrac{-(-6) \pm \sqrt{(-6)^2-4(5)(-2)}}{2(5)}$

$\implies x=\dfrac{6 \pm \sqrt{36+40}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{76}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{4 \cdot 19}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{4}\sqrt{19}}{10}$

$\implies x=\dfrac{6 \pm2\sqrt{19}}{10}$

$\implies x=\dfrac{3 \pm \sqrt{19}}{5}$

Therefore, the exact solutions to the given <u>quadratic equation</u> are:

$x=\dfrac{3 + \sqrt{19}}{5} \:\textsf{ and }\:x=\dfrac{3 - \sqrt{19}}{5}$

Learn more about the quadratic formula here:

brainly.com/question/28105589

brainly.com/question/27953354

3 0

1 year ago

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