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Kay [80]
3 years ago
6

Find the scale factor where the pre-image is the small triangle and the image is the large triangle.

Mathematics
2 answers:
allsm [11]3 years ago
8 0

Scale factor is the ratio of two corresponding sides.

Here we have two triangles, where the preimage is the smaller triangle and the image is the larger triangle.

So scale factor =14/18 = 7/9

And to find the missing variable, we need to set the ratio.

7/9 = 28/x

Cross multiplying both sides

7x = 28*9

x = 36

BARSIC [14]3 years ago
7 0

Answer:  The required scale factor is \dfrac{9}{7}.

Step-by-step explanation:  We are given to find the scale factor of the dilation from the small triangle to the large triangle.

We know that

scale factor of dilation is given by

S=\dfrac{\textup{length of a side of the dilated figure(D)}}{\textup{length of the corresponding side of the original figure(O)}}.

From the given picture, we have

D = 21 units and O = 27 units.

Therefore, the scale factor of dilation is given by

S=\dfrac{27}{21}=\dfrac{9}{7}.

Thus, the required scale factor is \dfrac{9}{7}.

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Answer:

B

Step-by-step explanation:

A is wrong, it increases

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8 0
3 years ago
Write the equation in slope-intercept form of the line that passes through
mixer [17]

Answer:

We conclude that the equation in slope-intercept form of the line that passes through  (12,9) and is perpendicular to the graph of y = -3/4x + 1 will be:

  • y=\frac{4}{3}x-7

Step-by-step explanation:

We know the slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given the line

y = -3/4x + 1

comparing with the slope-intercept form of the line equation

The slope = m = -3/4

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:  

slope = m = -3/4

Thus, the slope of the new perpendicular line = – 1/(-3/4) = 4/3

Using the point-slope form

y-y_1=m\left(x-x_1\right)

where m is the slope of the line and (x₁, y₁) is the point

substituting the values of the slope = 4/3 and the point (12, 9)

y-y_1=m\left(x-x_1\right)

y-9=\frac{4}{3}\left(x-12\right)

Add 9 to both sides

y-9+9=\frac{4}{3}\left(x-12\right)+9

y=\frac{4}{3}x-16+9

y=\frac{4}{3}x-7

Therefore, we conclude that the equation in slope-intercept form of the line that passes through  (12,9) and is perpendicular to the graph of y = -3/4x + 1 will be:

  • y=\frac{4}{3}x-7
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3 years ago
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3 years ago
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alexgriva [62]
I would think of it as this but i could be wrong.
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