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telo118 [61]
2 years ago
12

∫(sinxdx)/(sinx^3+cosx^3)

Mathematics
1 answer:
olga_2 [115]2 years ago
3 0
I answered this but i couldn’t take multiple pictures. however i found a website with the same answer as me after i answered your question. here : https://www.quora.com/How-do-I-integrate-Integrate-sinxdx-sin-3x+cos-3x
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What is b. -25b - 92=133
muminat
B = -9

You add 92 to 133 and divide by -25 which is -9. : D
6 0
3 years ago
Read 2 more answers
Can u help me answer this I’m so stuck
Slav-nsk [51]

Answer:

I learned a great formula for repeating decimals.

OK! Let's get started. For each decimal spot that is recurring, it is put over a 9, rather than a 10.

In your case, 0.142 would be 142 over 3 9s.

142/999 cannot be simplified.

Therefore, 142/999 is our answer.

Since the repentant is over only one digit, we have to solve another way.

We can represent it as "x"

10x = 5.66.... - x = 0.56.....=5.1

9x = 51/10

51/10/9 = 51/90 = 17/30 as our answer.

We can solve this next one the same way:

100x = 3.44444 - x  = 3.41

999x = 341/100

341/100/999 = 31/900 as our answer.

Now! 1.52 can be solved the same way.

In doing so, we achieve the answer 151/99 as our answer

This one can be done the same way as well. I'll give you the answer, but next time try to solve it for yourself!

179/495 is our answer.

Now, you asked for 0.004 as a fraction.

That is equivalent to 4/999 as our answer.

Note: This is because each 0 can be counted as a 9, increasing in order. (i.e., over 100 is over 99 over 1000 is over 999 over 10 9)

6 0
3 years ago
Helpppooo meeeee. !!!!!
Brrunno [24]

Answer:

The looks of the Triangles are different.

Step-by-step explanation:

3 0
3 years ago
What are the possible rational roots of the polynomial equation?<br><br> 0=2x7+3x5−9x2+6
RoseWind [281]

Answer: \pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0

Where:

- The coefficients are integers.

- a_n is the leading coeffcient (a_n\neq 0)

- a_0 is the constant term a_0\neq 0

Every rational root of the polynomial is in the form:

\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}

For the case of the given polynomial:

2x^7+3x^5-9x^2+6=0

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

 Then, by Rational Roots Test we get the possible rational roots of this polynomial:

\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

5 0
2 years ago
SOMEONE HELP ASAP PLZ!Z!!!!!
lina2011 [118]
The answer is obviously not A and B so that leaves us with only C or D and the one that id the best choice would have to be C because it gives good information about how it is used and where it would be installed 

Hope this helped : ) 
7 0
3 years ago
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