Answer:
1/5 gallon of water in each bottle
Step-by-step explain:
4/5 = 0.8
0.8/4 = 0.2 or 1/5 gallons
Erm..
9 I guess..
Good luck?
Answer:
I got x<equal to -11 or x>equal to4
Step-by-step explanation:
x^2+15x+44=0
(x+4)(x+11)=0(Factor left side of equation)
x+4=0 or x+11=0(Set factors equal to 0)
x=−4 or x=−11
Check intervals in between critical points. (Test values in the intervals to see if they work.)
x<−11(Works in original inequality)
−11<x<−4(Doesn't work in original inequality)
x>−4(Works in original inequality)
Answer:
x<−11 or x>−4
We have to present the number 41 as the sum of two squares of consecutive positive integers.
1² = 1
2² = 4
3² = 9
4² = 16
5² = 25
16 + 25 = 41
<h3>Answer: 4 and 5</h3>
Other method:
n, n + 1 - two consecutive positive integers
The equation:
n² + (n + 1)² = 41 <em>use (a + b)² = a² + 2ab + b²</em>
n² + n² + 2(n)(1) + 1² = 41
2n² + 2n + 1 = 41 <em>subtract 41 from both sides</em>
2n² + 2n - 40 = 0 <em>divide both sides by 2</em>
n² + n - 20 = 0
n² + 5n - 4n - 20= 0
n(n + 5) - 4(n + 5) = 0
(n + 5)(n - 4) = 0 ↔ n + 5 = 0 ∨ n - 4 =0
n = -5 < 0 ∨ n = 4 >0
n = 4
n + 1 = 4 + 1 = 5
<h3>Answer: 4 and 5.</h3>
9514 1404 393
Answer:
(64x^28)/(5y^22)
Step-by-step explanation:
The applicable rules of exponents are ...
(a^b)^c = a^(bc)
(a^b)(a^c) = a^(b+c)
(a^b)/(a^c) = a^(b-c)
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First, eliminate the outside exponent on the left factor. Then use the above rules to combine factors with the same base.
