Answer:
93
Step-by-step explanation:
Answer:
the answer should be 158 but I'm not a hundred percent sure
Yes you are correct. You divide both sides by -6 to isolate x. Dividing both sides by a negative number will flip the inequality sign.
If you need to graph this, then you'll have a closed circle at -12 on the number line. Then you'll have shading to the left of this closed circle. The closed circle indicates "include this endpoint as part of the shaded solution set".
Im going to say C hopefully I’m right
Answer:
(a)18
(b)1089
(c)Sunday
Step-by-step explanation:
The problem presented is an arithmetic sequence where:
- First Sunday, a=1
- Common Difference (Every subsequent Sunday), d=7
We want to determine the number of Sundays in the 120 days before Christmas.
(a)In an arithmetic sequence:

Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.
Therefore, Aldsworth advertised 18 times.
(b)Next, we want to determine the sum of the first 18 terms of the sequence
1,8,15,...

The sum of the numbers of days published in all the advertisements is 1089.
(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.