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icang [17]
3 years ago
6

Maureen is in charge of renting a climbing wall for the school’s fundraiser. The equation y = 170x represents the total cost of

renting a climbing wall from Company A. The table shows the relationship between cost and rental time for Company B. The graph shows the relationship for Company C. Which company, if any, offers the best deal? Explain.
Mathematics
2 answers:
Morgarella [4.7K]3 years ago
5 0

Answer:

company d

Step-by-step explanation:

mark brainliest

irina [24]3 years ago
3 0

Answer:

after 3 days, the total cost of renting a car from Discount car rentals or Payless car rentals is the same.

The difference between 2 days = $265 - $185 = $80

If the difference between 2 days = $80

Difference between 1 day = $80/2= $40

Step-by-step explanation:

Hopefully this helped, if not HMU and I will try my best to get u  a better answer! have a great day :)

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One Sunday, 120 days before Christmas, Aldsworth store publishes an advertisement saying ‘120 shopping days until Christmas'. Al
Lena [83]

Answer:

(a)18

(b)1089

(c)Sunday

Step-by-step explanation:

The problem presented is an arithmetic sequence where:

  • First Sunday, a=1
  • Common Difference (Every subsequent Sunday), d=7

We want to determine the number of Sundays in the 120 days before Christmas.

(a)In an arithmetic sequence:

\text{The nth term}, T_n=a+(n-1)d\\T_n \leq 120\\$Therefore:$\\1+7(n-1) \leq 120\\1+7n-7\leq 120\\7n-6\leq 120\\7n\leq 120+6\\7n\leq 126\\$Divide both sides by 7$\\n\leq 18

Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.

Therefore, Aldsworth advertised 18 times.

(b)Next, we want to determine the sum of the first 18 terms of the sequence

1,8,15,...

\text{Sum of a sequence}, S_n=\frac{n}{2}( 2a+(n-1)d)\\S_{18}=\frac{18}{2}( 2*1+(18-1)*7)\\=9(2+17*7)\\=9(2+119)\\=9*121\\S_{18}=1089

The sum of the numbers of days published in all the advertisements is 1089.

(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.

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