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Sever21 [200]
3 years ago
14

If 4 - 7x = 39 then what is the value of x + 1

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
8 0
4-7x=39
-4 = -4
7x=35
÷7. ÷7
35 divided by 7 equals 5. Therefore x=5. So, 5+1=6
Your final answer is 6.
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Solve using the quadratic formula: 2x^2=8x-7. There are four parts to this question labeled A-D.
Tasya [4]

3x=2+4x I think I don’t know
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27 divided by 55 using long division (please show work) HELP
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27 divided by 55= 0.490909 repeating
Step by Step Explanation:
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5 0
3 years ago
The width of a rectangle is 3 cm less than the length. What is the length if the width is 11 cm
Rudik [331]

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14

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7 0
2 years ago
What are the x and y intercepts of f(x) = x2-x-12/x2+5x+6 and is there a hole? ​
stiv31 [10]

Answer:

There are no holes. The VAs are x=4 & x=-4  the HA is  x=2 the x intercepts are  (-3,0) & (3,0)  and the y intercept is (0,9/8).

Step-by-step explanation:

Given  f ( x ) =2 x ^2 − 18/x^2-16

find all asymptotes, holes and intercepts.

Factor the numerator and denominator.

f ( x ) =2 ( x ^2 − 9 )/( x + 4 ) ( x − 4 )

f ( x ) =2 ( x +3 ) ( x − 3 )/( x + 4 ) ( x − 4 )

A hole exists when the numerator and denominator contain the same factor (a factor "cancels out"). This function has no holes.

To find the vertical asymptote(s) (VA), find the values of  x

which make the denominator equal zero. The function is undefined at these values of  x

because you cannot divide by zero.

Set each factor of the denominator equal to zero and solve.

x + 4 = 0  and x − 4 = 0

x = − 4  and  x = 4

These are the VAs.

To find the horizontal asymptote(HA), compare the degree of the numerator and denominator. If the degrees are the same, the HA is the ratio of the leading coefficients.

For  f ( x) =2 x ^2 − 18/x^2-16

the degree in both numerator and denominator is  2

and the ratio of the leading coefficients is 2/1=1

The HA is  x = 2

The  x  intercept is the value at which the function (or "y") equals zero. If the numerator is zero, the function equals zero.

2 ( x + 3 ) ( x − 3 ) = 0

x + 3 = 0    x − 3 = 0

x = − 3   and  x = − 3

The  x  intercepts are  ( − 3 , 0 )  and  ( 3 , 0 ) .

The  y  intercepts are found by setting  x = 0 .

f ( 0 ) = 2 ( 0 ) ^2 − 18/( 0 )^2 − 16 = 9 /8

The  y  intercept is  ( 0 , 9/ 8 ) .

graph{(2x^2-18)/(x^2-16) [-10.04, 9.96, -3.56, 6.44]}

HOPE THIS HELPS YOU!!!!

        =)

4 0
3 years ago
A geometric sequence is defined by the equation an = (3)3 − n.
Delvig [45]
PART A

The geometric sequence is defined by the equation

a_{n}=3^{3-n}

To find the first three terms, we put n=1,2,3

When n=1,

a_{1}=3^{3-1}

a_{1}=3^{2}

a_{1}=9
When n=2,

a_{2}=3^{3-2}
a_{2}=3^{1}

a_{2}=3

When n=3

a_{3}=3^{3-3}

a_{3}=3^{0}
a_{1}=1
The first three terms are,

9,3,1

PART B

The common ratio can be found using any two consecutive terms.

The common ratio is given by,
r= \frac{a_{2}}{a_{1}}
r = \frac{3}{9}

r = \frac{1}{3}

PART C

To find
a_{11}

We substitute n=11 into the equation of the geometric sequence.

a_{11} = {3}^{3 - 11}

This implies that,

a_{11} = {3}^{ - 8}

a_{11} = \frac{1}{ {3}^{8} }

a_{11}=\frac{1}{6561}
4 0
3 years ago
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