The correct answer is e. 3.57×10³ Al³+(aq) + 3e→AL(s) 4.00g of AL=4g/26.98 g/mol= 0.1483 mol t=znF/1 where t is time in seceonds. Z= valency number of ions of the substance or electrons which are transferred per ion F= Faraday's constant I = electric current in'A'CA C/s t=(3×0.1483 mol ×96485 C/mol) /12(C15) t=3577 second = 3.5 ×10³s
