All categories

3 years ago

Explain why the product at the negative electrode is not always a metal.

Chemistry

1 answer:

Elena-2011 [213]3 years ago

3 0

Answer:

Whether you get the metal or hydrogen during electrolysis depends on the position of the metal in the reactivity series: the metal will be produced if it is less reactive than hydrogen. hydrogen will be produced if the metal is more reactive than hydrogen.

You might be interested in

How many protons, and neutrons are in nuclide tin-115?

HACTEHA [7]

50 protons
65 neutrons

8 0

3 years ago

Read 2 more answers

What type of flower is this? This is for a science project.

kenny6666 [7]

I believe that is a plant called Wisteria.

4 0

3 years ago

Read 2 more answers

Is mass conserved when 200 g of water undergoes a physical change? Use complete sentences to support your answer by explaining h

andrew-mc [135]

Answer:

-200

Explanation:

7 0

3 years ago

Group the following electron configurations in pairs that would represent similar chemical properties at their atoms;

marishachu [46]

Answer: Pairs are: (a) and (d), (b) and (f), (c) and (e)

Explanation:

In a periodic table, elements are arranged in 18 vertical columns known as groups and 7 horizontal rows known as periods.

Elements arranged in a group show similar chemical properties because of the presence of same number of valence electrons.

Valence electrons are defined as the electrons which are present in the outermost shell of an atom. Outermost shell has the highest value of 'n' that is principal quantum number.

For the given options:

For a:

The given electronic configuration is: $1s^22s^22p^63s^2$

The number of valence electrons in the given configuration are 2

For b:

The given electronic configuration is: $1s^22s^22p^63s^3$

The number of valence electrons in the given configuration are [2 + 3] = 5

For c:

The given electronic configuration is: $1s^22s^22p^63s^23p^64s^23d^{10}4p^6$

The number of valence electrons in the given configuration are [2 + 6] = 8

For d:

The given electronic configuration is: $1s^22s^2$

The number of valence electrons in the given configuration are 2

For e:

The given electronic configuration is: $1s^22s^22p^6$

The number of valence electrons in the given configuration are [2 + 6] = 8

For f:

The given electronic configuration is: $1s^22s^22p^63s^23p^3$

The number of valence electrons in the given configuration are [2 + 3] = 5

Electronic configuration of (a) and (d) will form a pair, (b) and (f) will form a pair, (c) and (e) will form a pair and will have similar chemical properties.

Hence, the pairs are: (a) and (d), (b) and (f), (c) and (e)

4 0

3 years ago

Nnbvcvbnm,.,mnbvcxcvbjklkjhvbn

pav-90 [236]

This are letters of the alphabet some are periods and some are commas also they do not form any words or meaning
hope this helped ;)

3 0

3 years ago