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LekaFEV [45]
3 years ago
6

Can someone help me real quick PLEASE

Mathematics
1 answer:
suter [353]3 years ago
7 0

Answer:

The hexagon has an area of 220.6 square units.

Step-by-step explanation:

You can solve this by realising that the hexagon can be divided into 6 equilateral triangles of the same area.

The area of the triangle is the same as a rectangle of the same width and height, but divided by two, and we're told that the width of the side is 9.2, and the height is eight.  So the total area of the hexagon is:

6 × (9.2 × 8) / 2

= 9.2 × 24

= 220.6

So the hexagon has an area of 220.6 square units.

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Mnenie [13.5K]

The sum of the finite arithmetic series of  26 + 29 + 32 + 35 + 38 + 41 + 44 is 245. Arithmetic series is a sequence of number such that the difference between any term and the previous term is a constant number. When we sum a finite number of terms in the arithmetic series, we get the finite arithmetic series.

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2 years ago
PLS HELP IMA GIVE BRAIN LISTTT!!! <br><br> Which model is 85% shaded?<br> Done
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Answer:

First left

Step-by-step explanation:

17/20 =  0.85   = 85/100 = 85%

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3 years ago
A pound is equal to 0.454 kilograms, how many kilograms does a 142-pound man weigh
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Answer:

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Step-by-step explanation:

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3 years ago
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Part B
alisha [4.7K]

Question:

Consider ΔABC, whose vertices are A (2, 1), B (3, 3), and C (1, 6); let the line segment  AC represent the base of the triangle.

(a)  Find the equation of the line passing through B and perpendicular to the line AC

(b)  Let the point of intersection of line AC with the line you found in part A be point D. Find the coordinates of point D.

Answer:

y = \frac{1}{5}x + \frac{12}{5}

D = (\frac{43}{26},\frac{71}{26})

Step-by-step explanation:

Given

\triangle ABC

A = (2,1)

B = (3,3)

C = (1,6)

Solving (a): Line that passes through B, perpendicular to AC.

First, calculate the slope of AC

m = \frac{y_2 - y_1}{x_2 - x_1}

Where:

A = (2,1) --- (x_1,y_1)

C = (1,6) --- (x_2,y_2)

The slope is:

m = \frac{6- 1}{1 - 2}

m = \frac{5}{-1}

m = -5

The slope of the line that passes through B is calculated as:

m_2 = -\frac{1}{m} --- because it is perpendicular to AC.

So, we have:

m_2 = -\frac{1}{-5}

m_2 = \frac{1}{5}

The equation of the line is the calculated using:

m_2 = \frac{y_2 - y_1}{x_2 - x_1}

Where:

m_2 = \frac{1}{5}

B = (3,3) --- (x_1,y_1)

(x_2,y_2) = (x,y)

So, we have:

\frac{1}{5} = \frac{y - 3}{x - 3}

Cross multiply

5(y-3) = 1(x - 3)

5y - 15 = x - 3

5y  = x - 3 + 15

5y  = x +12

Make y the subject

y = \frac{1}{5}x + \frac{12}{5}

Solving (b): Point of intersection between AC and y = \frac{1}{5}x + \frac{12}{5}

First, calculate the equation of AC using:

y = m(x - x_1) + y_1

Where:

A = (2,1) --- (x_1,y_1)

m = -5

So:

y=-5(x - 2) + 1

y=-5x + 10 + 1

y=-5x + 11

So, we have:

y=-5x + 11 and y = \frac{1}{5}x + \frac{12}{5}

Equate both to solve for x

i.e.

y = y

-5x + 11 = \frac{1}{5}x + \frac{12}{5}

Collect like terms

-5x -\frac{1}{5}x = \frac{12}{5} - 11

Multiply through by 5

-25x-x = 12 - 55

Collect like terms

-26x = -43

Solve for x

x = \frac{-43}{-26}

x = \frac{43}{26}

Substitute x = \frac{43}{26} in y=-5x + 11

y = -5 * \frac{43}{26} + 11

y =  \frac{-5 *43}{26} + 11

Take LCM

y =  \frac{-5 *43+11 * 26}{26}

y =  \frac{71}{26}

Hence, the coordinates of D is:

D = (\frac{43}{26},\frac{71}{26})

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Answer:

8.1

Step-by-step explanation:

1.8 times 4.50 is 8.1

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