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LekaFEV [45]
3 years ago
6

Can someone help me real quick PLEASE

Mathematics
1 answer:
suter [353]3 years ago
7 0

Answer:

The hexagon has an area of 220.6 square units.

Step-by-step explanation:

You can solve this by realising that the hexagon can be divided into 6 equilateral triangles of the same area.

The area of the triangle is the same as a rectangle of the same width and height, but divided by two, and we're told that the width of the side is 9.2, and the height is eight.  So the total area of the hexagon is:

6 × (9.2 × 8) / 2

= 9.2 × 24

= 220.6

So the hexagon has an area of 220.6 square units.

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The perimeter of a pentagon (5 sides) is 10.5 centimeters. The sides are x,x,x,x and 1.7 cm. What is the value of x
Drupady [299]

Answer:

What did she sayyyyyyyy? Um I don't know what x,x,x,x is ma'am or sir

Step-by-step explanation:

4 0
3 years ago
an outdoor deck is 7 feet wide the perimeter of the deck is 64 feet what is the length of the deck use the numbers to write an e
ycow [4]
Answer: 25

Equation:
2(7)+2(x)=64
14+2x=64
2x=64
X=25

Hope this helps :)
5 0
3 years ago
How many square inches of tin are needed to make the top of a can that is 10 inches in diameter? A) 62.8 in2 B) 78.5 in2 C) 227
Xelga [282]
Area of a circle = PI*radius^2
10 inch diameter = 5 inch radius
Area = PI* 5^2
Area = <span> <span> <span> 78.5398163397 </span> </span> </span>
Answer is B)


8 0
3 years ago
Read 2 more answers
What is 10√94 simplified. Its not 98 or its decimal form.
slavikrds [6]

Answer:

hi

Step-by-step explanation:

i think 96(probably)

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3 0
2 years ago
The number of bacteria in a certain culture doubled every hour. If there were 30 bacteria present in the culture initially, how
vichka [17]

Answer:

The number of bacteria after 8th will be 3840

Step-by-step explanation:

Given the initially 30 bacteria present in the culture.

Also, the number of bacteria got doubled every hour.

So, using the equation

A=A_0r^{n-1}

Where A is number of bacteria after n hours.

A_0 is bacteria present initially.

r is the common ration, in our problem it is given that bacteria doubles every hour. So, r=2

And n is the number of hours. In our problem we need amount of bacteria at the end of 8th hours. So, n=8

Plugging values in the formula we get,

A=30(2)^{8-1}\\A=30\times 2^7\\A=30\times 128\\A=3840

So, number of bacteria after 8th will be 3840

3 0
3 years ago
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