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Sholpan [36]
3 years ago
10

Let f(x)=4x2−5 . A new quadratic function g(x) is the function f(x) stretched vertically by a factor of 2. What is the equation

of this new function g(x)? Question 5 options: g(x)=4x2−3 g(x)=8x2−10 g(x)=4(x+2)2−5 g(x)=8x2−5
Mathematics
1 answer:
soldi70 [24.7K]3 years ago
5 0
To vertically strech a function, f(x) by a factor of c, that is cf(x)

so strech vertically by 2 means times whole thing by 2
so
2 times (4x^2-5) =8x^2-10

g(x)=8x^2-10
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The sum of four and three multiplied by the quotient of four and two
asambeis [7]

Answer:

14

Step-by-step explanation:

4+3=7

4/2=2

7•2=14

8 0
3 years ago
Which are correct representations of inequality 6x>3+4(2x-1)
abruzzese [7]

The correct representations of inequality 6x>3+4(2x-1) will be 6x ≥ 3 + 8x – 4.Option B is correct

<h3>What is the definition of inequality?</h3>

Inequality is a sort of equation in which the equal sign is missing. As we will see, inequality is defined as a statement regarding the relative magnitude of two claims.

The complete question is;

"Which are correct representations of the inequality 6x ≥ 3 + 4(2x – 1)? Check all that apply.

A)1 ≥ 2x

B)6x ≥ 3 + 8x – 4"

6x ≥ 3 + 4(2x – 1)

6x≥3+8x-4

The correct representations of inequality 6x>3+4(2x-1) will be 6x ≥ 3 + 8x – 4.

Hence, option B is correct

To learn more about inequity, refer to brainly.com/question/20383699

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4 0
2 years ago
When Lily does a self-inventory, she lists her knowledge of Excel, her proficiency in bookkeeping, and her training in customer
Anika [276]

Answer:

The above mentioned qualities go under the category of abilities.

Step-by-step explanation:

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Ability is used to refer a person's native aptitude in a specific field.

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Hence her qualities come under the category of abilities.

6 0
3 years ago
Read the picture that's were the question is.
vlabodo [156]

Answer:

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4 0
3 years ago
John wants to make a 100 ml of 6% alcohol solution mixing a quantity of a 3% alcohol solution with an 8% alcohol solution. What
mart [117]

Answer:

-50 ml of 3% alcohol solution and 150 ml of 8% alcohol solution

Step-by-step explanation:

For us to solve this type of mixture problem, we must represent the problem in equations. This will be possible by interpreting the question.

Let the original volume of the first alcohol solution be represented with x.

The quantity of the first alcohol solution needed for the mixture is 3% of x

                   ⇒ \frac{3}{100} * x

                       = 0.03x

Let the original volume of the second alcohol solution be represented with y.

The quantity of the second alcohol solution needed for the mixture is 5% of y

                   ⇒ \frac{5}{100} * y

                       = 0.05y

The final mixture of alcohol solution is 6% of 100 ml

                 ⇒ \frac{6}{100} * 100 ml

                       = 6 ml

Sum of values of two alcohol solutions = Value of the final mixture

                     0.03x + 0.05y = 6 ml               ..........(1)

Sum of original quantity of each alcohol solution = Original volume of the of mixture

                     x + y = 100 ml                          ..........(2)      

For easy interpretation, I will be setting up a table to capture all information given in the question.

Component                       Unit Value      Quantity(ml)       Value

3% of Alcohol solution        0.03                 x                     0.03x

8% of Alcohol solution        0.08                 y                     0.08y

Mixture of 100ml of 6%        0.06               100                       6    

                                                                x + y = 100       0.03x + 0.08y =6

Looking at the equations we derived, we have two unknowns in two equations which is a simultaneous equation.

                                0.03x + 0.05y = 6 ml               ..........(1)

                                x + y = 100 ml                           ..........(2)    

Using substitution method to solve the simultaneous equation.

Making x the subject of formula from equation (2), we have,

                                x  = 100 - y                                 ..........(3)

Substituting  x  = 100 - y from equation (3) into equation (1)

                               0.03(100 - y) + 0.05y = 6  

                               3 - 0.03y + 0.05y = 6  

Rearranging the equation,            

                               0.05y - 0.03y = 6 - 3

                               0.02y = 3

                               y = \frac{3}{0.02}

                               y = 150 ml

Substituting y = 150 ml into equation (3) to get x

                              x  = 100 - 150 ml

                              x = - 50 ml

The quantity of the first alcohol solution needed for the mixture for 3% is - 50 ml

The quantity of the second alcohol solution needed for the mixture for 5% is 150 ml

This solution means 50 ml of the first alcohol solution must be removed from the mixture with 150 ml of the second alcohol solution to get a final mixture of 100 ml of 6% alcohol solution.

3 0
3 years ago
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