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3 years ago

11

The graph below is an example of which type of function? On a coordinate plane, a function decreases, has a point of inflection,

and then continues to decrease. quadratic linear cubic square root

2 answers:

natita [175]3 years ago

5 0

Answer: its cubic

Step-by-step explanation:

klasskru [66]3 years ago

4 0

Answer:

C

Step-by-step explanation:

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Please help quick will mark brainliest

Rzqust [24]

Answer: (-2,1) (-5,0) (-1,-4) are the cooridents for the reflection

Step-by-step explanation:

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3 years ago

At top cruising speed a mako shark can swim 4 km in 1/10 hour a blue whale can swim 5 km in 1/4 hour which animal swims faster a

oksian1 [2.3K]

Answer:

fortnite

Step-by-step explanation:

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3 years ago

Find the area of the figure. Use 3.14 for π.

siniylev [52]

Answer:

Area of the figure= $51.5feet^2$

Step-by-step explanation:

Area of the figure=Area of the middle rectangle+ Area the the two triangles

Area of the rectangle=Length*Width

$Length= 8+3 =11 feet\\\\Width=4 feet$

$Area = 11*4\\\\ =44 feet^2$

Area of the triangle with the height of 2 feet and base= 3 feet

Area= $\frac{1}{2} *Base*Height$

= $=\frac{1}{2} *3*2\\\\=\frac{1}{2}*6\\\\ =3 feet^2$

Area of the triangle with the Height=3 feet and Base= 3 feet

Area= $\frac{1}{2} *Base*Height$

$=\frac{1}{2}*3*3\\\\ =\frac{1}{2}*9\\\\ =4.5feet^2$

Total Area of the figure $=44+3+4.5=51.5 feet^2$

5 0

3 years ago

Read 2 more answers

How do the graphs of y =1/x and y = 3/x – 4 compare?

Pie

The graphs of y =1/x and y = 3/x – 4 can be compared by saying that c<span>ompared to the graph of y =1/x , the graph of y =3/x – 4 is a vertical stretch by a factor of 3 and a translation of 4 units down. This can be seen clearly when you graph the functions on a x-y coordinate plane.</span>

6 0

3 years ago

Find the equation of the line that passes through point A (1,7) and B (-3, -1)

amid [387]

Answer:

The equation of the line is 2 x - y + 5 = 0.

Step-by-step explanation:

Here the given points are A( 1, 7) & B( -3, - 1) -

Equation of a line whose points are given such that

( $x_{1}, y_{1}$ ) & ( $x_{2}, y_{2}$ )-

y - $y_{1}$ = $\frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }$ ( x - $x_{1}$ )

i.e. <em> y - 7= $\frac{- 1 - 7}{ -3-1}$ ( x- 1)</em>

<em> y - 7 = $\frac{- 8}{- 4}$ ( x -1)</em>

<em> y - 7 = 2 ( x - 1) </em>

<em> y - 7 = 2 x - 2</em>

<em> 2 x - y + 5 = 0</em>

Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1) is 2 x - y + 5 = 0.

6 0

3 years ago