Determine the slope-intercept form of the equation of the line parallel to y = x + 11 that passes through the point (–6, 2).
1 answer:
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We know, opposite sides are parallelogram is parallel, therefore slopes are equal.
Slope of line one :
So, equation of other line passing through (-4,5) and have slope of -0.5 is :
y-5 = -0.5( x-(-4))
y-5 = -0.5x - 2
y + 1/2x = 3
2y + x = 6
Therefore, equation of line containing the (-4, 5) is 2y + x = 6.
Hence, this is the required solution.