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lorasvet [3.4K]
3 years ago
15

A landscaping company placed two orders with a nursery. The first order was for 13 bushes and 4 trees, and totaled $327.50. The

second order was for 6 bushes and 2 trees, and totaled $142.96. Sam tried to use system of equation to solve the problem.
Mathematics
1 answer:
vladimir2022 [97]3 years ago
8 0

Answer:

Step-by-step explanation:

A landscaping company placed two orders with a nursery. Sam tried to use system of equation to solve the problem.

Let us represent

Cost of bushes = x

Cost of trees = y

The first order was for 13 bushes and 4 trees, and totaled $327.50.

Hence

13x + 4y = 327.5......Equation 1

The second order was for 6 bushes and 2 trees, and totaled $142.96.

Combined both Equations

13x + 4y = 327.5......Equation 1

6x + 2y = 142.96 ........ Equation 2

We solve using Elimination method

We Multiply Equation 1 by 2 and Equation 2 by 4 to Eliminate y

26x + 8y = 655 ..... Equation 3

24x + 8y = 571.84 ..... Equation 4

We substract Equation 4 from Equation 3

2x = 83.16

x = 83.16/2

x = $41.58

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y = 1

y = mx + b                                  <----- Slope-intercept form

1 = (3/10)(3) + b                           <----- Insert values

1 = 9/10 + b                                 <----- Multiply 3/10 and 3

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Now that we know the values for "m" and "b", we can construct the equation of the perpendicular line.

y = (3/10)x + 1/10

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