Let the message be M : 1001 0001 and the generator function is G : 1001
Solution :
CRC sender
<u> </u>
1001 | 1001 0001 000
<u> 1001 </u>
<u> 0000 0001 </u>
1000
<u> 1001 </u>
0001 000
<u> 1 001 </u>
0001
Here the generator is 4 bit - 1, so we have to take three 0's which will be replaced by reminder before sending to received--
eg 1001 0001 001
Now CRC receiver
<u> </u>
1001 | 1001 0001 001
<u> 1001 </u>
0000 0001
<u> 1001 </u>
1000
<u> 1001 </u>
0001 001
<u> 0001 001 </u>
0000
No error
It is true that in the array implementation of a queue, the pop operation is most efficient if the front of the queue is fixed at index position. The correct option is a.
<h3>What is pop operation? </h3>
The removal of an element is referred to as a pop operation. Again, because we only have access to the element at the top of the stack, we can only remove one element. We simply take the top of the stack off.
A push operation decrements the pointer before copying data to the stack; a pop operation copies data from the stack before incrementing the pointer.
The pop operation in an array implementation of a queue is most efficient if the queue's front is fixed at index position.
Thus, the correct option is a.
For more details regarding pop operation, visit:
brainly.com/question/15172555
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