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2 years ago

In triangle WXY , angle X cong angle W YW = 19 and WX = 15 15. Find the length of XY.

Mathematics

1 answer:

ivolga24 [154]2 years ago

4 0

Answer:

Step-by-step explanation:

Given the triangle WXY, with angle X and W to be equal, this shows that the triangle is an isosceles triangle. An isosceles triangle is the one which has two of its sides and its base angle to be the same.

If <X = <W, then The sides YW = XY

That is the other two sides asides from the side XW are equal.

Since YW = 19

Hence the measure of the side XY will also be 19

YW = XY = 19

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Write the equation of a line that is perpendicular to the given line and that passes through the given point. y= 2/3x + 9 ; (–6,

matrenka [14]

Answer:

y = - $\frac{3}{2}$ x - 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = $\frac{2}{3}$ x + 9 ← is in slope- intercept form

with slope m = $\frac{2}{3}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{\frac{2}{3} }$ = - $\frac{3}{2}$ , thus

y = - $\frac{3}{2}$ x + c ← is the partial equation

To find c substitute (- 6, 5) into the partial equation

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3 years ago

Explain what the slope of a linear relationship is.

Brums [2.3K]

The slope is the same as rate of change. In a linear graph, it is the change in y over the change in x.

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3 years ago

Write the equation for the graphed function. I worked out y = 5 - 4 (x + 4)^2 but that isn't right. Any help would be appreciate

alexira [117]

Vertex form for a parabola with vertex (p,q) is

$y = a(x-p)^2 + q$

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$2 = a(-3 - -4)^2 + 5$

$2 = a + 5$

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Putting it together,

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The question is not clearly readable, but I'm assuming the expression which makes more sense, so you can have a clue

Answer:

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Step-by-step explanation:

Powers of The Imaginary Unit

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$i=\sqrt{-1}$

The first powers of i are

$i^0=1$

$i^1=i$

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$i^3=i.i^2=-i$

$i^4=i^2.i^2=1$

And so on the cycle repeats every four numbers. To find the value of $i^{96}$ we can find the remainder of 96/4=0. So $i^{96}=i^0=1$

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Factoring

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