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sergeinik [125]

2 years ago

11

Choose the correct preposition to complete the sentence. To facilitate a quick getaway, the cunning thief parked the car perpend

icular the building.

2 answers:

Otrada [13]2 years ago

8 0

Answer:

C. To

Step-by-step explanation:

edg 2020

Vlad1618 [11]2 years ago

5 0

Answer:

The answer is TO

Step-by-step explanation:

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Write the following phrase as a variable expression. Use X to represent “a number.” The sum of eleven, a number, and the product

melamori03 [73]

Answer:

11 + x + 19*x

Step-by-step explanation:

The sum of eleven, a number, and the product of nineteen and the number.

we have to read carefully and understand how to interpret

when he says the sum of separates into 3 parts because there is a "comma" and an "and"

Now let's separate the 3 parts of the sum

1 part

says eleven so we just put 11

eleven = 11

2 part

in the text it says that we replace "a number" with x

a number = x

3 part

In this case we simply make the product between the given values

the product of nineteen and the number

19 * x

Now we can accommodate everything and we finish

11 + x + 19*x

6 0

3 years ago

Select the number property that will justify the step in the following expression.

Airida [17]

Two of the numbers were switched in a multiplication equation, so the answer would be commutative- multiplication.

7 0

3 years ago

Read 2 more answers

I need help with this badddddddddd

tiny-mole [99]

Answer:

She forgot to add the zero when she multiplied 27 x 50

Step-by-step explanation:

If you need one ask me I can try my best to explain

5 0

3 years ago

T<29. graph your inequality for problem number 3

Pepsi [2]

I graphed it. First you choose a number that’s less than 29 and greater than 29 which I chose 0 and 100 but it didn’t let me show the whole picture

4 0

3 years ago

Solve for XX. Assume XX is a 2×22×2 matrix and II denotes the 2×22×2 identity matrix. Do not use decimal numbers in your answer.

sveticcg [70]

The question is incomplete. The complete question is as follows:

Solve for X. Assume X is a 2x2 matrix and I denotes the 2x2 identity matrix. Do not use decimal numbers in your answer. If there are fractions, leave them unevaluated.

$\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]$ · X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ =<em>I</em>.

First, we have to identify the matrix <em>I. </em>As it was said, the matrix is the identiy matrix, which means

<em>I</em> = $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

So, $\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]$ · X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

Isolating the X, we have

X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]$ - $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

Resolving:

X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{ccc}2-1&8-0\\-6-0&-9-1\end{array}\right]$

X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]$

Now, we have a problem similar to A.X=B. To solve it and because we don't divide matrices, we do X=A⁻¹·B. In this case,

X= $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ ⁻¹· $\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]$

Now, a matrix with index -1 is called Inverse Matrix and is calculated as: A . A⁻¹ = I.

So,

$\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ · $\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]$ = $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

9a - 3b = 1

7a - 6b = 0

9c - 3d = 0

7c - 6d = 1

Resolving these equations, we have a= $\frac{2}{11}$ ; b= $\frac{7}{33}$ ; c= $\frac{-1}{11}$ and d= $\frac{-3}{11}$ . Substituting:

X= $\left[\begin{array}{ccc}\frac{2}{11} &\frac{-1}{11} \\\frac{7}{33}&\frac{-3}{11} \end{array}\right]$ · $\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]$

Multiplying the matrices, we have

X= $\left[\begin{array}{ccc}\frac{8}{11} &\frac{26}{11} \\\frac{39}{11}&\frac{198}{11} \end{array}\right]$

6 0

3 years ago