Answer:
x = 500 yd
y = 250 yd
A(max) = 125000 yd²
Step-by-step explanation:
Let´s call x the side parallel to the stream ( only one side to be fenced )
y the other side of the rectangular area
Then the perimeter of the rectangle is p = 2*x + 2* y ( but only 1 x will be fenced)
p = x + 2*y
1000 = x + 2 * y ⇒ y = (1000 - x )/ 2
And A(r) = x * y
Are as fuction of x
A(x) = x * ( 1000 - x ) / 2
A(x) = 1000*x / 2 - x² / 2
A´(x) = 500 - 2*x/2
A´(x) = 0 500 - x = 0
x = 500 yd
To find out if this value will bring function A to a maximum value we get the second derivative
C´´(x) = -1 C´´(x) < 0 then efectevly we got a maximum at x = 500
The side y = ( 1000 - x ) / 2
y = 500/ 2
y = 250 yd
A(max) = 250 * 500
A(max) = 125000 yd²
Answer: (3, 13)
Step-by-step explanation:
If we let the point be P, then AP:BP=2:1.
I believe the answer is 16
Answer:
the number (x) is 120.
Explanation:
<em>100% + 60% = 160% = 1.6 </em>
<em />
<em>(just multiply it by 1.6 because it is equal to 60%)</em>
Answer:
The area of a label is 
Step-by-step explanation:
we know that
The lateral area of a cylinder (label of the can) is equal to
we have that
A can is 4 inches wide
so
The diameter of the can is 4 inches
----> the radius is half the diameter
----> height of the label
substitute in the formula
