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3 years ago

Drag each percent to match the situation. Each percent may be used only once.

Mathematics

1 answer:

Svetllana [295]3 years ago

7 0

Answer:

1:80%

2:95%

3:15%

4:33 1/2%

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Find the common ratio of the geometric sequence 36, 6, 1, 16, ... . Write your answer as an integer or fraction in simplest form

nalin [4]

Answer:

Step-by-step explanation:

The common ratio is the constant found by dividing any term by the previous term.

r=6/36=1/6

r=1/6

I am assuming the 16 at the end of the sequence was a typo. IF 16 was at the end of the sequence it is NOT a geometric sequence as there would not be a common ratio for all terms.

7 0

3 years ago

Help ASAP and pls tell me how thanks

bulgar [2K]

I have no clue ooooo mmmmyyyyy goooshhhh

6 0

3 years ago

.....................

Allisa [31]

Answer:

Step-by-step explanation:

We require to calculate the volume of 1 brick

V = lbh ( l is length, b is breadth and h is height ), that is

V = 14 × 8 × 5 = 560 cm³

Now divide the volume of concrete available by the volume of 1 brick.

number of bricks made = $\frac{16800}{560}$ = 30

5 0

3 years ago

Find the coordinates of P ' if D o, 2.4 (x,y) is applied to the triangle below

guajiro [1.7K]

Answer:

The coordinates of P' are (4.8,-4.8).

Step-by-step explanation:

The rule of dilation $D_{o,2.4}(x,y)$ represent the dilation with scale factor 2.4 and center at origin.

If the scale factor of the dilation is k and the center is (0,0), then

$(x,y)\rightarrow (kx,ky)$

Since the scale factor is 2.4, therefore

$(x,y)\rightarrow (2.4x,2.4y)$

From the given figure it is noticed that the coordinates of P are (2,-2). The coordinates of P' are

$P(2,-2)\rightarrow P'(2.4(2),2.4(-2))$

$P(2,-2)\rightarrow P'(4.8,-4.8)$

Therefore the coordinates of P' are (4.8,-4.8).

3 0

3 years ago

If a(n)=24 which recursive formula could represent the sequence below? <br> ...,24,88,664,8408,...

sesenic [268]

24= 3*2^3
88= 11*2^3
664= 83*2^3 -> 83=11+72 = 11 + 2^3*3^2
664=2^3 (11+2^3*3^2) = 88 +(2^3*2^3*3^2) = 88 +(24^2)

8408= 1051 * 2^3 -> 1051= 83+968 -> 968 = 2^3 * 11^2
8408= 2^3 (83+2^3*11^2) = 664 +(2^3*2^3*11^2) = 664 +(88^2)

So:
a(n) = a(n-1) + a(n-2)^2

Lets check: 88+24^2= 664
664+88^2= 8408

3 1

3 years ago