9514 1404 393
Answer:
7/3
Step-by-step explanation:
The point at the right end of segment 5 is 7 units above and 3 units to the right of the point at the left end. The slope is the "rise" divided by the "run":
slope = m = rise/run = 7/3
The slope of segment 5 is 7/3.
Answer:
<em>x+y=4</em>
Step-by-step explanation:
hello :
note : by identity you have x²-y² = (x-y)(x+y)
in this exercice : 2x²-2y² = 2(x²-y²) = 2 (x-y)(x+y)
means : 2 (x-y)(x+y) = 40
but x-y = 5
so : 2(5)(x+y) =40
x+y=40/10
<em>x+y=4</em>
59° + 81°+ x° = 180°
140° + x° = 180°
x = 40°
1/8÷1/4
Flip over the second fraction
1/4=4/1
1/8 *4/1
Cross out 8 and 4 ,divide by 4
8/4=2
4/4=1
1/2 *1/1=1/2
Answer: 1/2
First, we need to set up our two equations. For the picture of this scenario, there is one length (L) and two widths (W) because the beach removes one of the lengths. We will have a perimeter equation and an area equation.
P = L + 2W
A = L * W
Now that we have our equations, we need to plug in what we know, which is the 40m of rope.
40 = L + 2W
A = L * W
Then, we need to solve for one of the variables in the perimeter equation. I will solve for L.
L = 40 - 2W
Now, we can substitute the value for L into L in the area equation and get a quadratic equation.
A = W(40 - 2W)
A = -2W^2 - 40W
The maximum area will occur where the derivative equals 0, or at the absolute value of the x-value of the vertex of the parabola.
V = -b/2a
V = 40/2(2) = 40/4 = 10
Derivative:
-4w - 40 = 0
-4w = 40
w = |-10| = 10
To find the other dimension, use the perimeter equation.
40 = L + 2(10)
40 = L + 20
L = 20m
Therefore, the dimensions of the area are 10m by 20m.
Hope this helps!
