-3t ≥39
-3t/-3 ≥39/-3
t≤-13
is your answer hope this helps
Note: only flip the sign when you are dividing a negative number
Answer:
The population of deer at any given time = 200(e^0.03t) ÷ (1.5 + (e^0.03t))
Step-by-step explanation:
This is an example of logistic equation on population growth
carrying capacity, k = 200
Rate, r = 3% = 0.03
Initial Population, P1 = 80
P(t) =?
P(t) = (P1 (k)(e^rt)) ÷ (k- P1 + P1(e^rt))
P(t) = (80 (200)(e^0.03t)) ÷ (200 - 80 + 80(e^0.03t))
= (16000(e^0.03t)) ÷ (120 + 80(e^0.03t))
= 200(e^0.03t) ÷ (1.5 + (e^0.03t))
The variation equation is p = kr^2
<h3>How to determine the variation equation?</h3>
The variables are give as:
Pressure = P
Radius= r
The direct variation from p to the square of r is represented as:
Express as an equation
p = kr^2
Where k represents the constant of variation
Hence, the variation equation is p = kr^2
Read more about variation at:
brainly.com/question/6499629
#SPJ1
Answer:
It's the first choice y = (-5/2)x - 1.
Step-by-step explanation:
First find the slope of the line 5x + 2y = 12 by converting to slope-intercept form.
5x + 2y = 12
2y = -5x + 12
y = (-5/2)x + 6 so the slope is (-5/2).
The line we require had also a slope of -5/2 because it is parallel to the first line and it also passes through the point (-2, 4). So:
y - 4 = (-5/2)(x - -2) (the point-slope form)
y - 4 = (-5/2)(x + 2)
y = (-5/2)x - 5 + 4
y = (-5/2)x - 1 (answer)
