Answer: where is the question (and if you think I wrote this to get the points your wrong its because I cant comment ok) so now please show me the question for me and other people to answer.
Step-by-step explanation:
Should be option 1. i cant really gv an explanation tho sry :/
Answer:
The answer is All integers where n ≥ 1
Hope this helps!
Whenever a problem says "one number" and "another number" we can substitute x and y. for this we have x=2y+1 and xy=1. since we know the value of x (2y+1) we can substitute it for the other equation to get (2y+1)y=10. simplify to get 2y^2+y=10. from here you can do a few methods to solve this, but the simplest in my opinion is by factoring.
In order to factor it must be equal to 0, so we have 2y^2+y-10=0. We factor this and get y=5 (we also get y=-4 but it is an extraneous root). now we can plug that into either equation and find that x=2.
this means our two numbers are 5 and 2
Answer:
x = 12.48
y = 13.22
Step-by-step explanation
Im not sure if its correct
10^2 + b^2 = 16^2
100 + b^2 = 256
b^2 = √156
b = 12.48
b= 12 ( If needed to round to the nearest whole number)
a^2 + 15^2 = 20^2
a^2 + 225 = 400
a^2 = √175
a = 13.22
a = 13 ( If needed to round to nearest whole number)
