Answer:
The picture is 4.25 inches from the side of the paper
Step-by-step explanation:
- Taylor wants to center a 3.5 inch picture on a piece of paper that is
12 inches wide
- Lets think about that he want to put the picture in the center of the
paper, then divide the length of the paper into two equal parts and the
picture into two equal part
∵ The width of the paper is 12 inches
∵ 12 ÷ 2 = 6 inches
∵ The width of the picture is 3.5 inches
∵ 3.5 ÷ 2 = 1.75
- Now lets subtract from 6 inches (half paper) 1.75 inches (half picture)
to find the distance between the side of the paper and the picture
∵ 6 - 1.75 = 4.25
∴ The distance from the side of the paper to the picture is 4.25 inches
* <em>The picture is 4.25 inches from the side of the paper</em>
* Look to attached figure for more understand
<h2>
Answer:</h2>
<u>The cost would be </u><u>$15.86</u>
<h2>
Step-by-step explanation:</h2>
The cost of 1 steak is $6.10
The cost of 2 3/5 steaks will be
Cost of 2 3/5 steaks = 6.10 * 2 3/5
Cost of 2 3/5 steaks = $15.86
The answer is zero point four three
You could also write this answer as 0.43
Answer:
62.29%
Step-by-step explanation:
The probability of Aya being offered a coupon on at least one of the six days she visits the website is 100% minus the probability that she is not offered a coupon on any of the six days, which is described by a binomial probability with zero successes in six trials with a probability of succes p = 0.15.

The probability that Aya will be offered a coupon on at least one of the days she visits the website is 62.29%.