Eight point sevenhundreth twenty-three thousandths
Answer:
Option (A)
Step-by-step explanation:
By the characteristics of a quadrilateral given in the question,
1). All four sides are congruent.
It may be Square, Rhombus
2). Both the pairs of opposite sides are parallel.
It may be Parallelogram, Rhombus.
3). Diagonals are perpendicular.
It may be Rhombus, Rectangle, Square.
Since all three characteristics define the properties of a Rhombus,
The given quadrilateral matches with a rhombus.
Therefore, Option (A) will be the answer.
<h3>
Answer: sometimes true</h3>
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Explanation:
The plane P can be thought of a perfectly flat ground. Now imagine a flag pole which represents line GH. If AB is drawn in chalk on the pavement, and this line AB intersects the base of the flagpole, then we've made AB and GH intersect. However, this example shows that GH is <u>not</u> on the plane P.
Is it possible to have GH be in the the plane? Yes. We could easily draw another chalk line on the ground to have it intersect AB somewhere. But as the previous paragraph says, it's also possible that GH is not in the plane.
Therefore, the statement is sometimes true
Answer:
the sides the formula for that is 2(pi)radius(height). the formula for the total surface area is 2(pi)radius(height) + 2(pi)radius squared.
