Answer:
The total surface area of triangular pyramid is 172 cm squared
Step-by-step explanation:
Triangular pyramid:
- Number of faces 4.
- Number of vertices of a triangular pyramid is 6.
- The volume is
. A= area of the pyramid's base and H= height of the pyramid.
- The surface area of triangular pyramid B+L. B= area of base, L= area of lateral surface.
Given that, the area of the base is 43 cm squared. Lateral faces with bases of 10 cm and heights 8.6 cm.
The 3 sides of the triangular pyramid is triangle in shape.
The area of triangle is 
.
The lateral surface area of the triangular pyramid is
cm squared
=129 cm squared
The total surface area of triangular pyramid is
=Area of the base + lateral surface area
=(43+129) cm squared
=172 cm squared
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Answer:
442.5 feet^2
Step-by-step explanation:
So this figure is an octagonal prism.
First off we need to find the area of the two octagons.
The formula for the area is 2(1+ to the square root of 2)a^2.
The a is one side value and in this case it is 4 so plug that in and you get 77.25 feet^2.
The same steps apply for the bottom octagon but we don’t have to do that because it is the same as the top one.
So adding up the two octagons is 154.5 feet^2.
Now time for the rectangles.
In total there are 8 rectangles and a really easy way to do this is finding the area of one rectangle and multiplying that by 8.
So the length is 9 and the width is 4 and when you multiply that together you get 36.
Then multiply 36 by 8 and you will get 288 feet^2.
So when you add up 288 and 154.5 you will get 442.5 feet^2 as your final answer.
