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3 years ago

Why Uranium consider as non-renewable resource? Please I need it now and short answer with simple meaning!!

1 answer:

5 0

Rate in its natural state uranium -235 is a non renewable energy. although small quantities go a long way .For example the fission of one pound of uranium release more energy than burning three million pounds of coal.Nuclear fission reacts splits atoms to release the enriched uranium.

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Gordon throws a baseball into the air. It rises, stops when it reaches its greatest height, and then falls back to the ground. A

Ivahew [28]

That would be when the baseball is rising. The energy from the throw is kinetic energy.

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3 years ago

Read 2 more answers

Problem #6 If you dissolve lead (II) nitrate and potassium iodide in water they will react to form lead (II) iodide and potassiu

LenaWriter [7]

$\implies \huge \tt \underline \red{answer}$

Should ever come back

8 0

3 years ago

How many total ions are in 2.95 g of magnesium sulfite?

Aleksandr [31]

Answer:

Approximately $5.65 \times 10^{-2}\; \rm mol$ , which is approximately $3.41 \times 10^{22}$ particles.

Explanation:

Formula of magnesium sulfite: $\rm MgSO_3$ .

Look up the relative atomic mass of $\rm Mg$ . $\rm S$ , and $\rm O$ on a modern periodic table:

$\rm Mg$ : $24.305$ .
$\rm S$ : $32.06$ .
$\rm O$ : $15.999$ .

The ionic compound $\rm MgSO_3$ consist of magnesium ions $\rm {Mg}^{2+}$ and sulfite ions $\rm {SO_3}^{2-}$ .

Notice that $\rm {Mg}^{2+}\!$ and $\rm {SO_3}^{2-}\!$ combine at a one-to-one ratio to form the neural compound $\rm MgSO_3$ . Therefore, each $\rm MgSO_3\!$ formula unit would include one $\rm {Mg}^{2+}$ ion and one $\rm {SO_3}^{2-}$ ion (that would be two ions in total).

Calculate the formula mass of one such formula unit:

$\begin{aligned}&\; M(\mathrm{MgSO_3}) \\ = & \; 24.305 + 32.06 + 3 \times 15.999 \\ = & \; 104.362\; \rm g \cdot mol^{-1}\end{aligned}$ .

In other words, the mass of one mole of $\rm MgSO_3$ formula units (which includes one mole of $\rm {Mg}^{2+}$ ions and one mole of $\rm {SO_3}^{2-}$ ions) would be $104.362\; \rm g$ .

Calculate the number of moles of such formula units in that $2.95\; \rm g$ of $\rm MgSO_3$ :

$\begin{aligned}n&= \frac{m}{M}\\ &=\frac{2.95\; \rm g}{104.362\; \rm g \cdot mol^{-1}} \approx 2.82670 \times 10^{-2}\; \rm mol\end{aligned}$ .

There are two moles of ions in each mole of $\rm MgSO_3$ formula units. Therefore, that $2.82670 \times 10^{-2}\; \rm mol$ of $\rm MgSO_3\!$ formula units would include approximately $2 \times 2.82670 \times 10^{-2}\; \rm mol \approx 5.65\times 10^{-2}\; \rm mol$ of ions.

8 0

3 years ago

A solution is made by dissolving 62.42 g of ammonium sulfate in enough

natulia [17]

Answer:

9.46 M

Explanation:

Molarity is a measure of the molar concentration of a solution. It can be calculated by the following formula

Molarity = number of moles/volume

Using moles = mass/molar mass

Molar Mass of Ammonium sulfate (NH₄)₂SO₄ =

{14 + 1(4)}2 + 32 + 16(4)

= {14 + 4}2 + 32 + 64

= 18(2) + 96

= 36 + 96

= 132g/mol

mole = mass/molar mass

mole = 62.42 ÷ 132

mole = 0.473mol

- Molarity = mole ÷ volume

Volume = 50.0 mL = 50/1000 = 0.05 L

Molarity = 0.473 ÷ 0.05

Molarity = 9.46 M

3 0

3 years ago

Think about a wooden chair and a balloon. what do these two objects always have in common?

MakcuM [25]

They are both made out of atoms!

7 0

3 years ago