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yawa3891 [41]
2 years ago
7

What is the percent nitrogen in NaNO3? 56.47% 27.04% 16.48% 14.01%

Chemistry
1 answer:
hichkok12 [17]2 years ago
3 0
I think it’s :answer choice c
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Atoms A and X are fictional atoms. Suppose that the standard potential for the reduction of X^2+ is +0.51 V, and the standard po
IRINA_888 [86]

If you are given the standard potential for the reduction of X^2+ is +0.51 V, and the standard potential for the reduction of A^2+ is -0.33, just add the two. The standard potential for an electrochemical cell with the cell is 0.18V

5 0
3 years ago
Read 2 more answers
Can someone please help me on #17? I don’t get it :(
Dmitry [639]
Given is the specific heat of water equal to 4.18 Joule per gram per *C.

This means to raise the temperature of 1 g of water by 1 degree Celsius we need 4.18 joule of energy.

Now, look at the question. We are asked that how much amount of energy would be required to raise the temperature of 25 g of water by (54-50) = 4 degree celsius.

To do so we have formula

Q = m C (temperature difference)

Have a look at pic for answer

5 0
3 years ago
A volume of 80.0 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. I
murzikaleks [220]

Answer:

The mass of the steel bar is 26.833 grams

Explanation:

<u>Step 1: </u>data given

ΣQ gained = ΣQ lost

Q=m*C*ΔT

with m = mass in grams

with C= specific heat capacity ( in J/(g°C))

with ΔT = change in temperature = T2-T1

Qsteel = Qwater

msteel * Csteel * (T2steel - T1steel) = mwater * Cwater * (T2water - T1water)

Mass of steel = TO BE  DETERMINED

mass of water =⇒ since 1mL = 1g : 80 mL = 80g

Csteel =0.452 J/(g °C

Cwater = 4.18 J/(g °C

initial temperature steel T1 : 2 °C

final temperature steel T2 = 21.3 °C

initial temperature water T1 =22 °C

final temperature water T2 = 21.3 °C

<u>Step 2:</u> Calculate mass of steel

msteel * Csteel * (T2steel - T1steel) = mwater * Cwater * (T2water - T1water)

msteel * 0.452 *(21.3-2) = 80 * 4.18 * (21.3-22)

msteel = (80 * 4.18 * (-0.7)) / (0.452 * 19.3)

msteel = -234.08 / 8.7236

msteel = -26.833 g

Since mass can't be negative we should take the absolute value of it = 26.833g

The mass of the steel bar is 26.833 grams

6 0
3 years ago
Slicing an average loaf of bread gives 13 medium thickness slices. Each slice of bread is to be coated with 0.0500 oz of mayonna
AlexFokin [52]

Answer:

36 loaves of bread and 18.48 ounces of mayonnaise are needed to make all of the sandwiches.

Explanation:

Number of slices of ham = 231

Given that each sandwich has 1 slice of ham.

Then 231 slices of ham will be in :

1\times 231 =231 sandwiches

A single sandwich is made up of 2 bread slices , Then bread slices in 231 sandwiches will be :

231\times 2=462

Each bread slice is applied with 0.0500 ounce of mayonnaise.

Then 462 bread slices will have :

462\times 0.0500 ounces=18.48 Oz

1 bread loaf = 13 bread slices

Then breads loves in 462  bread slices :

\frac{462}{13}=35.54\approx 36

36 loaves of bread and 18.48 ounces of mayonnaise are needed to make all of the sandwiches.

8 0
4 years ago
*blank* carry blood away from the heart, while *blank* carry blood back to the heart.
worty [1.4K]

Answer:

i think its C im not so sure

Explanation:

nrjdkfkzhsugogo

5 0
3 years ago
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